The correct order would be:
1. A tree absorbs the carbon from the atmosphere into its leaves for photosynthesis;
2. A caterpillar gets the carbon by eating the tree's leaves.
3. A bird gets the carbon by eating the caterpillar.
4. The bird flies into a building and dies instantly. It falls to the ground.
5. The bird decomposes and the carbon returns to the atmosphere.
The carbon cycle is very similar to the water cycle, though it has its own unique ways. Once the carbon is released into the atmosphere, it will either be absorbed by the vegetation, or go up into the higher parts of the atmosphere. If it is absorbed by the vegetation, the organisms that eat the vegetation will get it in them. When the predators eat those organism they get the carbon into their organisms. When the predators die, they start to decompose. When they decompose, the carbon is released from them and it returns to the atmosphere, and the whole process goes all over again.
Answer:
9/16
Explanation:
Let broad, straight wings be represented by the allele W. Homozygous condition will be WW or ww while heterozygous condition will be Ww
Let pale-colored body with dark transverse stripes is represented by C. Homozygous condition will be CC or cc while heterozygous condition will be Cc.
Heterozygous condition for both trait will be WwCc. Hence a mating between two flies that are heterozygous for both trait will be;
WwCc x WwCc
This will yield offspring in the following phenotypic ratio;
Broad, straight wings with pale-colored body/dark transverse stripes - 9/16
Broad, straight wings with ebony body colour - 3/16
Nubby, vestigial wings with pale-colored body/dark transverse stripes - 3/16
Nubby, vestigial wings with ebony body colour - 1/16.
See the attached image for the Punnet square result of the cross.
The proportion is 9/16
The right answer is <em>Bacillus.</em>
The pH-sensitive green fluorescent dye conjugates (available for <em>E.coli</em> and <em>Staphylococcus aureus</em>), give an accurate and faster results than other phagocytosis assay.
These conjugates are non-fluorescent in the extracellular medium (at neutral pH), but fluoresce will be brightly green at acidic pH such as in phagosomes, which makes it an ideal tool for phagocytosis assay.