Answer:
a) not one to one function; horizontal line intersects the graph of the function more than once.
b) yes it's a one to one function; the graph passes the horizontal line test
c) not one to one function; the graph doesn't pass the horizontal line test
d) yes it's a one to one function; the horizontal line doesn't intersect the function more than once
Step-by-step explanation:
5.
angle STQ is the supplementary angle (together they are 180° below line MQ) to 2x + 8.
above ST we have a group of 3 angles that combine to 180° :
2x + 8
90°
71 - x
so, to get x first :
2x + 8 + 90 + 71 - x = 180
x + 169 = 180
x = 11
so, the angle MTS =
2x + 8 = 2×11 + 8 = 22 + 8 = 30°.
6.
therefore, the angle STQ is
180 - angle MTS = 180 - 30 = 150°.
Answer:
T₂ = 421.4 K
Step-by-step explanation:
The temperature, T, of a given mass of gas varies inversely with its Volume,V.
We have,
V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K
V₂ = 70 cm₃
We need to find the new temperature of the gas. Using the above relation to find T₂.
Hence, the required temperature of the gas is 421.4 K.
Okay, so it might be a little difficult to explain it but here we go:
You find the LCD (lowest common denominator) and multiply the top and bottom half of the fraction by the LCD:
(1/x) times xy (since it is divisible by both x and y)
then you do the same for the bottom (2/y) times xy
The x's on the top cancel out leaving you with 1/y
The y's on the bottom cancel out leaving you with 2/x
So now you multiple the top half (numerator) by the reciprocal of the denominator. In other words, multiply (1/y) by (x/2).
The answer is x/2y
