Difference between the area of the triangle and square is 25
Step-by-step explanation:
- Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.
Area of the triangle = 
where s = 
⇒ s = (6 + 8 + 10)/2 = 24/2 = 12
= 
= 
= 
= 24 sq. units
- Step 2: Find the area of the square with perimeter = 28 units.
Perimeter of the square = 4 × side = 28
⇒ Side of the square = 28/4 = 7 units
⇒ Area of the square = (side)² = 7² = 49 sq. units
- Step 3: Find the difference between the area of the square and triangle.
Difference = 49 - 24 = 25
Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
Answer:
I am stuck at 2m^2 + 6m- 32 as finding the roots of the quadratic equation is unproductive
Answer:
x=90 degree
y=30 degree
Step-by-step explanation:
