Pattie runs at 5 ft/sec
She has got a head start of 15 feet.
So after 1 second, Pattie runs = (5+15) ft
<span>
= 20 </span>
ft
After 2 second Pattie runs = (20+5)ft
= 25 ft
After 3 second Pattie runs = (25+5) ft
= 30 ft
After 4 seconds Pattie runs = (30+5) ft
= 35 ft
After 5 seconds Pattie runs = (35+5) ft
= 40 ft
After 6 seconds Pattie runs = (40+5) ft
= 45 ft
Now Keith runs at 8 ft/sec
After 1 second Keith runs = 8 ft
After 2 second Keith runs = (8+8) ft
= 16 ft
After 3 second Keith runs = (16+8) ft
= 24 ft
After 4 second Keith runs = (24+8) ft
= 32 ft
After 5 second Keith runs = (32+8) ft
= 40 ft
After 6 second Keith runs = (40+8) ft
= 48 ft
So Pattie will stay ahead of Keith upto 4 seconds. In the 5th second Pattie and Keith will be level and in the 6th second Pattie will be overtaken by Keith.
The mean is the average. To find it, you add all of the numbers together.
2 + 8.7 + 11.9 + 3.3 + 4.2 + 2.2 + 13.4 = 45.7
Now you divide the total by the amount of numbers you added. Because you added 7 numbers, you divide 45.7 by 7.
45.7 ÷ 7 = 6.52 (This is the mean.)
To find the median you have to put all of the numbers in order of least to greatest.
2 2.2 3.3 4.2 8.7 11.9 13.4
The median is the number in the very middle. In this case, it is 4.2.
Answer:
Step-by-step explanation:
200 = 100%
80 = x%
200x = 8000
x = 40% (percentage increase)
400 = 200%
100 = 50%
500 = 200% + 50%
500 = 250% (the other percentage increase)
Answer:
A: 6c=75 If there were 6 movies then 6 times the cost of each movie would equal 75.
B:$12.50 We divide 75 by 6.
C: d+75=100 the cost left on the card plus 75 will equal 100.
D: $25 We subtract 75 from 100
Hope this helps :)
<em>-ilovejiminssi♡</em>
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
