Someone Help me solve these by substitution please !
1 answer:
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The tangent to at the point (0, 5) has a slope equal to the derivative evaluated at
.
This tangent passes through the point (0, 5), so its equation is
The normal line passes through the same point, but is perpendicular to the tangent line, so its slope is the negative reciprocal of the slope of the tangent. So the equation for the normal line is
Answer:
-3 times the square root of 5
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Explanation:
Let
Replace all the root 5 terms with x and we go from
to
From here, combine like terms to get
and the last thing to do is replace the x with sqrt(5)
Meaning that,