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Valentin [98]
3 years ago
15

Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
kolezko [41]3 years ago
4 0

The 2nd one or either the last one, I suggest the last one hope this helps!!

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What is the first quartile of the data displayed in this box-and-whisker plot?
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Since Q1 is the first part of the box plot, and on the graph states
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There has been much media coverage of the high cost of medicinal drugs in the United States. One concern is the large variation
umka21 [38]

Data for the question :

102.05 99.85 112.3 97.15 111.23 105.37 105.64 106.5 102.97 107.82 106.36 111.24 107.28 114.14 106.28 106.96 98.25 111.55 107.75 101.02 101.12 97.7 97.66 100.54 115.77 112.91 111.04 112.15 102.87 101.14 107.13 108.56 109.56 103.57 108.68 104.59 116.74 116.22 100.22 103.97 111.2 109.34 115.78 101.59 107.93 104.23 96.25 103.84 102.47 102.96 99.26 101.42 108.58 107.69 99.88 102.71 111.25 99.4 117.04 106.35 110.44 102.34 107.25 107.63 105.2 109.14 115.54 101.51 108.49 112.32 109.27 97.54 102.46 105.94 109.42 111.05 102.63 106.99 102.03 108.84 118.8 108.64 95.35 105.47 104.45 102.15 111.4 108.27 104.82 108.4 109.05 116.11 103.7 121.2 99.62 102.81 109.56 103.35 113.02 103.79

Answer:

Range = 25.35

Variance = 29.46

Standard deviation = 5.43

The variation in price of Prozac is high

Step-by-step explanation:

The range of the data :

Maximum - Minimum.

121.2 - 95.35 = 25.35

The variance, s :

s² = Σ(X - m²) / n - 1

Mean, m = Σx / n

X = individual data point

m = mean of data

n = sample size

Using a calculator of save time and ensure accuracy :

s² = 29.45522

The standard deviation, s

s = sqrt(variance)

s = sqrt(s²)

s = sqrt(29.45522)

s = 5.42726.

The range, variance and standard deviation, all measure the degree of variation in a dataset. The values of these statistical measure obtain for the price of 1 product across different pharmaceutical stores, suggests thatvthe variation in price is high;

With a range of about 25.35 and standard deviation of 5.43

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2 years ago
Passe os numeros a seguir para notação cientifica.
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Answer:

ingles Hablas ingles?

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3 years ago
The television station has received/A many complaints about/B
NARA [144]

<u>The television station has received/A many complaints about/B the clothing advertisements, which some/C viewers condemn to be/D </u><u>tasteless</u><u>. No error/E</u>

The correct option is D.

  • The television station has received many complaints about the clothing advertisements, which some viewers complained were tasteless.
  • Well, you could mean that  Writing Question is a 'trick one' .

What is a television station called?

  • Most often the term "television station" refers to a station which broadcasts structured content to an audience or it refers to the organization that operates the station.
  • A terrestrial television transmission can occur via analog television signals or, more recently, via digital television signals.

Learn more about television station

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We are given a sequence of five non-zero numbers, where the sum of each term and its neighboring terms is 15 or 25. Find the sum
PSYCHO15rus [73]

We have a sequence that meets the given criteria, and with that information, we want to get the sum of all the terms in the sequence.

We will see that the sum tends to infinity.

So we have 5 terms;

A, B, C, D, E.

We know that the sum of each term and its neighboring terms is 15 or 25.

then:

  • A + B + C = 15 or 25
  • B + C + D = 15 or 25
  • C + D + E = 15 or 25

Now, we want to find the sum of all the terms in the sequence (not only the 5 given).

Then let's assume we write the sum of infinite terms as:

a_1 + a_2 + a_3 + a_4 + a_5 + a_6 + ...

Now we group that sum in pairs of 3 consecutive terms, so we get:

(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) + ...

So we will have a sum of infinite of these, and each one of these is equal to 15 or 25 (both positive numbers). So when we sum that infinite times (even if we always have the smaller number, 15) the sum will tend to be infinite.

Then we have:

(a_1 + a_2 + a_3) + (a_4 + a_5 + a_6) +  ... \to \infty

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