Ask question

Ask question

All categories

3 years ago

13

A friend of yours is wearing a green shirt. Why is their shirt green?

1 answer:

IRISSAK [1]3 years ago

4 0

Answer:

The answer is the shirt would disappear because I would eat him

You might be interested in

Use the drop-down menu to answer the question. In the equation I = v over r , what does I stand for? please help

ExtremeBDS [4]

Answer:

Current

Explanation:

The equation you mentioned is also known as Ohm's law, which can be applied for any circuit containing a battery and one (or more) resistors:

$V=IR$

where

V is the voltage

I is the current

R is the resistance

We can re-arrange the equation and rewrite it explicitely for I, the current, to match the equation mentioned in the text of the question, and we have:

$I=\frac{V}{R}$

6 0

3 years ago

Read 2 more answers

Ball B, with a mass of 30kg, is moving to the left at 10 m/s. With what velocity should ball A, with a mass of 10kg, move to the

bogdanovich [222]

Using the conservation of momentumwhere momentum = mass x velocity
so the let x be the initial velocity of the ball B

(30 kg) (-10 m/s) + (10 kg) (x) = (30 kg) (30 m/s) + ( 10 kg) (-10 m/s)
-300 + 10 x = 900 - 10010x = 900 - 100 + 30010x = 1100x = 1100 / 10x = 110 m/s

6 0

3 years ago

Two cars are traveling at the same speed of 27 m/s on a curve thathas a radius of 120 m. Car A has a mass of 1100 kg and car B h

Lera25 [3.4K]

Answer:

$a_{cA} = 6.075$ m/s²

$a_{cB} = 6.075$ m/s²

$F_{cA} = 6682.5 N$

$F_{cB} = 9720 N$

Explanation:

Normal or centripetal acceleration measures change in speed direction over time. Its expression is given by:

$a_{c} = \frac{v^{2} }{r}$ Formula 1

Where:

$a_{c}$ : Is the normal or centripetal acceleration of the body ( m/s²)

v: It is the magnitude of the tangential velocity of the body at the given point

.(m/s)

r: It is the radius of curvature. (m)

Newton's second law:

∑F = m*a Formula ( 2)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

Data

$v_{A} = 27 \frac{m}{s}$

$v_{B} = 27 \frac{m}{s}$

$m_{A} = 1100 kg$

$m_{B} = 1600 kg$

r= 120 m

Problem development

We replace data in formula (1) to calculate centripetal acceleration:

$a_{cA} = \frac{(27)^{2} }{120}$

$a_{cA} = 6.075$ m/s²

$a_{cB} = \frac{(27)^{2} }{120}$

$a_{cB} = 6.075$ m/s²

We replace data in formula (2) to calculate centripetal force Fc) :

$F_{cA} = m_{A} *a_{cA} = 1100kg*6.075\frac{m}{s^{2} }$

$F_{cA} = 6682.5 N$

$F_{cB} = m_{B} *a_{cB} = 1600kg*6.075\frac{m}{s^{2} }$

$F_{cB} = 9720 N$

4 0

4 years ago

2. What is the percent composition of sulfur in H2SO4?

allochka39001 [22]

Answer:

C. 32.7%

Explanation:

% composition = ( mass S / mass H2SO4 ) × 100 = 32.08/ 98.10 × 100 = 32.7 % pls mark brainliest

6 0

3 years ago

What are the wavelengths of electromagnetic wave in free space that have the following frequencies?

Ne4ueva [31]

Explanation:

Given that,

(a) Frequency, $f_1=4\times 10^{19}\ Hz$

All electromagnetic wave moves with the speed of light. It is given by :

$c=f\lambda$

$\lambda_1=\dfrac{c}{f_1}\\\\\lambda_1=\dfrac{3\times 10^8}{4\times 10^{19}}\\\\\lambda_1=7.5\times 10^{-12}$

(b) Frequency, $f_2=5.5\times 10^{1=9}\ Hz$

All electromagnetic wave moves with the speed of light. It is given by :

$c=f\lambda$

$\lambda_2=\dfrac{c}{f_2}\\\\\lambda_2=\dfrac{3\times 10^8}{5.5\times 10^{9}}\\\\\lambda_2=0.054\ m$

Hence, this is the required solution.

7 0

3 years ago