Answer:
Explanation:
The displacement is the distnce of the shopper from the starting point.
Sum of movement along the vertical = 40-20 = 20m
Movement along the horizontal (x direction) = 15.0m
Displacement will be gotten using the pythagoras theorem.
d = √20²+ 15²
d = √400+225
d = √625
d = 25.0m
Hence the shoppers total displacement is 25.0m
Answer:
F = 789 Newton
Explanation:
Given that,
Speed of the car, v = 10 m/s
Radius of circular path, r = 30 m
Mass of the passenger, m = 60 kg
To find :
The normal force exerted by the seat of the car when the it is at the bottom of the depression.
Solution,
Normal force acting on the car at the bottom of the depression is the sum of centripetal force and its weight.



N = 788.6 Newton
N = 789 Newton
So, the normal force exerted by the seat of the car is 789 Newton.
Answer:
Option E is correct.
Time the ball remains in the air before striking the ground is closest to 3.64 s
Explanation:
yբ = yᵢ + uᵧt + gt²/2
yբ = 0
yᵢ = 2 m
uᵧ = u sinθ = 20 sin 60 = 17.32 m/s
g = -9.8 m/s², t = ?
0 = 2 + 17.32t - 4.9t²
4.9t² - 17.32t - 2 = 0
Solving the quadratic equation,
t = 3.647 s or t = -0.1112 s
time is a positive variable, hence, t = 3.647 s. Option E.
Answer:
in science and engineering , the weight of an object is the force acting on the object due to gravity.