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marta [7]
3 years ago
14

What total distance will a sound wave travel in air in 3.00 seconds at stp?

Physics
1 answer:
dimaraw [331]3 years ago
4 0
At stp conditions (T=0^{\circ}C), the speed of sound is
v=331.2 m/s
The sound wave moves by uniform motion, so we can use the basic relationship between space, time and velocity:
S=vt
where S is the distance covered by the sound wave in a time t. In our problem, t=3.00 s, therefore the distance covered by the sound wave is
S=vt=(331.2 m/s)(3.00 s)=993.6 m
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What conclusion can be draw about the heat of fusion of water from the heating curve?
PtichkaEL [24]

Answer: C) The kinetic energy and the entropy of the water molecules increases through fusion.

Explanation:

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The journey of an electron through an external circuit involves a long and slow zigzag path that is characterized by losses in e
Kitty [74]

Answer:

d_{b} = 2 d_{a}

Explanation:

The electrical resistance for a cylindrical wire is described by the expression

         R = ρ L / A

The area of ​​a circle is

     A = π r²

     r = d / 2

     A = π d²/4

We substitute

      R = ρ L  4 /π d²

Let's apply this expression to our case, they indicate that the resistance of wire A is 4 times the resistance of wire B

    R_{a} = 4 R_{b}

We substitute

    ρ  4/π d_{a}² = 4 (ρ  4/π d_{b}²)

    1 / d_{a}² = 4 / d_{b}²

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4 0
2 years ago
Please help me on this
Fynjy0 [20]

combustion of fossil fuels would be the correct answer when dealing with the alteration of the carbon cycle.

3 0
3 years ago
Near the top of the Citigroup Center building in New York City, there is an object with mass of 4.8 x 105 kg on springs that hav
Vikki [24]

Answer:

The force constant is  k =1.316 *10^{7} \  N/m

The energy stored in the spring is  E =  1.68 *10^{7} \ J

Explanation:

From the question we are told that

   The mass of the object is  M  = 4.8*10^{5} \ kg

    The period is T  = 1.2 \ s

The period of the spring oscillation is  mathematically represented as

         T  =2 \pi \sqrt{ \frac{M}{k}}

where  k is the force constant

   So making k the subject

       k = \frac{4 \pi ^2 M }{T^2}

substituting values

       k = \frac{4 (3.142) ^2 (4.8 *10^{5}) }{(1.2)^2}

      k =1.316 *10^{7} \  N/m

The energy stored in the spring is mathematically represented  as

       E =  \frac{1}{2} k x^2

Where x is the spring displacement which is given as

        x =  1.6 \ m

substituting values

      E =  \frac{1}{2} (1.316 *10^{7}) (1.6)^2

       E =  1.68 *10^{7} \ J

   

7 0
3 years ago
A uniform log of length L is inclined 30° from the horizontal when supported by a frictionless rock located 0.6L from its left e
mafiozo [28]

Answer:

x = 0.974 L

Explanation:

given,

length of inclination of log = 30°

mass of log = 200 Kg

rock is located at = 0.6 L

L is the length of the log

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let x be the distance from left at which log is horizontal.

For log to be horizontal system should be in equilibrium

 ∑ M = 0

mass of the log will be concentrated at the center  

distance of rock from CM of log = 0.1 L

now,

∑ M = 0

m_{log} g \times 0.1 L = m_{engineer} g \times (x - 0.6 L)

200 \times 0.1 L = 53.5 \times (x - 0.6 L)

0.374 L =x - 0.6 L

       x = 0.974 L

hence, distance of the engineer from the left side is equal to x = 0.974 L

7 0
3 years ago
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