The concepts used to solve this exercise are given through the calculation of distances (from the Moon to the earth and vice versa) as well as the gravitational potential energy.
By definition the gravitational potential energy is given by,
Where,
m = Mass of Moon
G = Gravitational Universal Constant
M = Mass of Ocean
r = Radius
First we calculate the mass through the ratio given by density.
PART A) Gravitational potential energy of the Moon–Pacific Ocean system when the Pacific is facing away from the Moon
Now we define the radius at the most distant point
Then the potential energy at this point would be,
PART B) when Earth has rotated so that the Pacific Ocean faces toward the Moon.
At the nearest point we perform the same as the previous process, we calculate the radius
The we calculate the Potential gravitational energy,
<h2>
Answer: process of converting matter into energy</h2><h2>
</h2>
Nuclear fission consists of dividing a heavy nucleus into two or more lighter or smaller nuclei, by means of the bombardment with neutrons to make it unstable. In this process that takes place in the atomic nucleus, neutrons, gamma rays and <u>large amounts of energy are emitted. </u>
Then, with this division a great release of energy occurs and the emission of two or three neutrons, other particles and gamma rays.
This means fission is a process in which energy is released by the separation of the components of the nucleous of the atom.
In other words:
<h2>Matter is converted to energy .</h2>
Answer:
In physics, work is defined as the use of force to move an object. For work to be done, the force must be applied in the same direction that the object moves. Work is directly related to both the force applied to an object and the distance the object moves. <em>[I HOPE THIS HELPS* PLS MARK ME BRAINLIEST]</em>
Answer:
a) CI^- ⇒ CI2 + 2e^-
b) 4.2 * 10^9 amperes
c) 1.4 * 10^10 watts
Explanation:
Given data:
Annual production of C12 = 45 millions tons per year
Typical plant operational percentage = 90%
Operating voltage of a cell = 3.4 v
A) Half-cell reaction for oxidation chloride to form chlorine
CI^- ⇒ CI2 + 2e^-
B) Calculate the total current worldwide needed to generate the global supply of CI 2
Total current = 
= 
= 4.2 * 10^9 amperes
Q = charge , t = time
C ) Calculate electrical power need to produce global supply of chlorine using electrolysis
P = V*I
= 3.4 * 4.2 * 10^9
= 1.4 * 10^10 watts
Answer:
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