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3 years ago

27. Improvements in space technology have greatly helped scientists better understand the stars, planets, and other

Physics

1 answer:

stellarik [79]3 years ago

8 0

Answer:

Explanation:

Technological advancements in astronomy have led to the development of thousands of products such as

new materials, medical devices, and communications satellites.

For example, the production of instruments like telescopes, microscopes, and other measuring devices now enables us to identify things that we couldn't examine with the naked eye.

Similarly, the development of communication satellites has led to the emergence and improvements in the mobile network industry.

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a geosynchronous satellite appears to remain over one spot on earth. a geosynchronous satellite has an orbital radius of 4.23 ×

Natasha2012 [34]

Given that,

radius, r = 4.23 x 10∧7 m

Period, T = ?

Since, we know that,

In a geosynchronous satellite, period is equal to the period of earth that is 24 hrs.

Therefore, Time period is equal to 24 hours.

8 0

3 years ago

1) A force of 157 N is applied to a box 25o above the horizontal. If it is applied over a distance of 14.5 m how much work is do

vfiekz [6]

Work done is given by

$W = F.d cos\theta$

here we know that

F = 157 N

d = 14.5

$\theta = 25^0$

now from the above formula

$W = (157)(14.5)cos25 = 2063.2 J$

By energy conservation

Initial total potential energy of egg = final total kinetic energy of egg

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

$v = \sqrt{2(9.8)(8.2)}$

$v = 12.7 m/s$

By momentum conservation we know that

$m_1v_1 = (m_1 + m_2)v$

$215(9.5) = (215 + 19.7) v$

$v = \frac{215 (9.5)}{215 + 19.7}$

$v = 8.7 m/s$

by momentum conservation we know that

$m_1v_1 + m_2v_2 = (m_1 + m_2) v$

let direction of velocity of Jay Z car motion is positive direction

now we will say

$1100(-20) + 1475v = (1100 + 1475)(7)$

$1475 v = 2575(7) + 1100(20)$

$v = 27.14 m/s$

Yes Jay Z is overspeeding as his speed is more than speed limit

Tension force in the string will be centripetal force

so here we can say

$T = \frac{mv^2}{R}$

here we know that

m = 0.63 kg

v = 7.8 m/s

R = 0.23 m

$T = \frac{0.63 (7.8)^2}{0.23}$

$T = 166.6 N$

6 0

3 years ago

An electric drill transfers 200 J of energy into a useful kinetic energy store. It also transfers 44 J of energy by sound and 48

kramer

Answer:

Er = 108 [J]

Explanation:

To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.

200 - 44 - 48 = Er

Where:

Er = remaining energy [J]

Er = 108 [J]

3 0

3 years ago

A molecular motor moves along a microtubule track in steps of 100 Å displacements. The motor hydrolyzes one molecule of ATP per

fredd [130]

Answer: F= 10⁻¹¹ N

Explanation:

We are given that a molecular motor moves in steps of 100 Å.

The energy change for ATP hydrolysis is –60 kJ•mol⁻¹

Now we have to find the maximum resistive force against which motor can move cargo.

So the force will be equal to the energy value divided by the distance in meters.

F= $\frac{-60}{100*10^{-10} }$ = −6000000000

Ignoring the minus sign.

And for one molecule of ATP per step, the value is divided by Avogadro's number.

F= $\frac{6000000000}{6.02*10^{23} }$

F= 10⁻¹¹ N

6 0

3 years ago

A radioactive nucleus has a half-life of 5*108 years. Assuming that a sample of rock (say, in an asteroid) solidified right afte

Gre4nikov [31]

Answer:

0.002

Explanation:

The half-life of the radioactive nucleus is related to its quantity, by the following equation:

$N_{t} = N_{0}2^{-t/t_{1/2}}$

Where:

N(t): is the quantity of the radioactive nucleus at time t

N₀: is the initial quantity of the radioactive nucleus

t: is the time = 4.5x10⁹ years

t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years

$\frac{N_{t}}{N_{0}} = 2^{-4.5 \cdot 10^{9} y/5 \cdot 10^{8} y} = 2 \cdot 10^{-3}$

Therefore, the fraction of the radioactive element in the rock today is 0.002.

I hope it helps you!

7 0

3 years ago