Answer:
0.243 m/s
Explanation:
From law of conservation of motion,
mu+m'u' = V(m+m')................. Equation 1
Where m = mass of the first car, m' = mass of the second car, initial velocity of the first car, u' = initial velocity of the second car, V = Final velocity of both cars.
make V the subject of the equation
V = (mu+m'u')/(m+m')................. Equation 2
Given: m = 260000 kg, u = 0.32 m/s, m' = 52500 kg, u' = -0.14 m/s
Substitute into equation 2
V = (260000×0.32+52500×(-0.14))/(260000+52500)
V = (83200-7350)/312500
V = 75850/312500
V = 0.243 m/s
Answer:
#See solution for details.
Explanation:
1.
Tools:
.
:Calculate the speed of the wave using the time,
it takes to travel along the rope. Rope's length,
is measured using the meter stick.
-Attach one end of rope to a wall or post, shake from the unfixed end to generate a pulse. Measure the the time it takes for the pulse to reach the wall once it starts traveling using the stopwatch.
-Speed of the pulse can then be obtained as:
: Apply force of known value to the rope then use the following relation equation to find the speed of a pulse that travels on the rope.
-Use the measuring stick and measuring scale to determine 
values of the rope then obtain 
.
-Use the force measuring constant to determine 
. These values can the be substituted in to obtain 
No, one more group must get the same result as the other group. This will make it more reliable and reproducible.
