Answer:
The common difference is -5/4
T(n) = T(0) - 5n/4,
where T(0) can be any number. d = -5/4
Assuming T(0) = 0, then first term
T(1) = 0 -5/4 = -5/4
Step-by-step explanation:
T(n) = T(0) + n*d
Let
S1 = T(x) + T(x+1) + T(x+2) + T(x+3) = 4*T(0) + (x + x+1 + x+2 + x+3)d = 240
S2 = T(x+4) + T(x+5) + T(x+6) + T(x+7) = 4*T(0) + (x+5 + x+6 + x+7 + x+8)d = 220
S2 - S1
= 4*T(0) + (x+5 + x+6 + x+7 + x+8)d - (4*T(0) + (x+1 + x+2 + x+3 + x+4)d)
= (5+6+7+8 - 1 -2-3-4)d
= 4(4)d
= 16d
Since S2=220, S1 = 240
220-240 = 16d
d = -20/16 = -5/4
Since T(0) has not been defined, it could be any number.
f(x) = 2x^2 - x - 10
Part A:
x-intercepts: (-2,0), (5/2,0)
Part B:
The vertex is the minimum
vertex: (1/4, -81/8)
Part C:
A:
x: -2, -1, 1/4, 1, 2
y: 0, -7, -81/8, -9, -4
B:
Answer:
Step-by-step explanation:
B
Hope I heped
Answer:
Terms: 6m , -2n, 7
Coefficients: 6, -2
Constants: 7
Step-by-step explanation:
terms are the parts of the expression so 6m, -2n and 7
coefficients are the numbers in fron tof variables so 6 and -2
constants are terms without variables so 7
