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vlabodo [156]
3 years ago
11

When the head of a match burns, chemical reaction is taking place. But a certain amount of energy is required to get this reacti

on started. This is the reactions activation energy. Describe where this energy comes from. What provides this energy?
Chemistry
1 answer:
Assoli18 [71]3 years ago
6 0

Answer:

Rubbing the match against a rough surface

The activation energy is provided by friction between surfaces

Explanation:

Activation energy is the energy required to start a chemical reaction. It is the minimum energy that must be supplied for a reaction to proceed.

When we strike a match against a rough surface, what we are trying to do is to supply the required activation energy in the form of friction in order to get the combustion reaction started.

Hence, the activation energy for the combustion of a match head is supplied by friction when the match head is struck against a rough surface.

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4 0
2 years ago
Calculate the number of calories needed to increase the temperature of 50.0 g of copper metal from 21.0 degrees C to 75.0 degree
KonstantinChe [14]
<h3>Answer:</h3>

1031.4 Calories.

<h3>Explanation:</h3>

We are given;

Mass of the copper metal = 50.0 g

Initial temperature = 21.0 °C

Final temperature, = 75°C

Change in temperature = 54°C

Specific heat capacity of copper = 0.382 Cal/g°C

We are required to calculate the amount of heat in calories required to raise the temperature of the copper metal;

Quantity of heat is given by the formula,

Q = Mass × specific heat capacity × change in temperature

   = 50.0 g × 0.382 Cal/g°C × 54 °C

   = 1031.4 Calories

Thus, the amount of heat energy required is 1031.4 Calories.

4 0
3 years ago
An unknown gaseous substance has a density of 1.06 g/L at 31 °C and 371 torr. If the substance has the following percent composi
Anarel [89]

Answer:

C) C4H6 - Right answer

Explanation:

Let's combine the Ideal Gases Law with density to get the molecular formula for the unknown gas.

Density = mass / volume

1.06 g /L means that 1.06 grams of compound occupy 1 liter of volume.

P . V = n . R . T

Pressure in Torr must be converted to atm

760 Torr are 1 atm

371 Torr  are __ (371 .1)/760 = 0.488 atm

0.488 atm . 1L = 1.06g/MM . 0.082 . 304K

(0.488 atm . 1L) / 0.082 . 304K = 1.06g/ MM

Mass / Molar mass = Moles → That's why the 1.06 g / MM

0.0195 mol = 1.06g / MM

1.06g/0.0195 mol = MM →  54.3 g/m

Now, let's use the composition

100 g of compound have 88.8 g of C

54.3 g of compound have ___ (54.3  . 88.8) /100 = 48 g of C

100 g of compound have 11.2 g of H

54.3 g of compound have __ (54.3  .  11.2)/100 = 6 g of H

48 g of C are included un 4 atoms

6 g of H are included in 6 atoms

4 0
3 years ago
What volume does .0685 mol of gas occupy at STP? 1mole =22.4
GuDViN [60]
V = nRT/P
V = 0.685 mol*(.0821 L*atm/K*mol)*273 K/1 atm
4 0
3 years ago
Read 2 more answers
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