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3 years ago

How does nuclear fission produce energy answer.com?

2 answers:

7 0

Nuclear energy originates from splitting of uranium atoms a process called fission. This generates heat to produce steam.

Hope this helps❤️

stich3 [128]3 years ago

7 0

Answer:

Nuclear fission is described as a phenomenon that causes an atom to dissociate into smaller atoms, during the split energy is produced.

Explanation:

Nuclear fission can be used as a source of power generation by nuclear plants, but does possess environmental concerns.

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The analysis of a compound gives the following percent composition by mass:

boyakko [2]

Answer:

C15 H31 O4 S

Explanation:

molecular formula is also the same because the value of "n" is 1

5 0

2 years ago

4. An 82 kg hiker climbs Mt. Humphrey near Flagstaff. During a two hour period, the hiker's

bazaltina [42]

Answer:

$\Delta E = 434253.96\,J$ , $\Delta P = 60.313\,W$

Explanation:

The change in energy is given by the change in gravitational potential energy:

$\Delta E = m\cdot g \cdot \Delta h$

$\Delta E = (82\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot (540\,m)$

$\Delta E = 434253.96\,J$

The average rate of change in terms of time is approximately this:

$\Delta P = \frac{\Delta E}{\Delta t}$

$\Delta P = \frac{434253.96\,J}{(2\,h)\cdot (\frac{3600\,s}{1\,h} )}$

$\Delta P = 60.313\,W$

8 0

2 years ago

What name should be used for the ionic compound LiI?

timurjin [86]

What name should be used for the ionic compound LiI?

The name that should be used for the ionic compound LiI is Lithium iodide. When naming ionic compounds, you have to take into consideration pairing of two components.

5 0

2 years ago

Read 2 more answers

If 25.5g of sodium thiosulphate was dissolved in 40g of distilled water at 25°C,

zhenek [66]

Answer:

Formula: Na2S2O3

we get solubility.

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

Solution given:

mass of sodium thiosulphate [m1]=25.5g

mass of water [m2]=40g

at temperature [t]=25°C

we have

solubility in g/dm^3 : $\frac{solute in gram}{solvent in gram} *100$

= $\frac{25.5}{40}*100$
=63.75g /litre=63.75g/dm³

solubility in g/dm^3 :63.75g/dm³

now

solubility of the solute in mol/dm^3=:63.75g/dm³/178=0.4 mol/dm³

6 0

2 years ago

If 287 mL of a 1.6 M glucose solution is diluted to 412 mL , what is the molarity of the diluted solution

satela [25.4K]

Answer:

The answer to your question is 1.11 M

Explanation:

Data

volume 1 = 287 ml

concentration 1 = 1.6 M

volume 2= 412 ml

concentration 2 = ?

Formula

Volume 1 x concentration 1 = Volume 2 x concentration 2

Solve for concentration 2

concentration 2 = (volume 1 x concentration 1) / volume 2

Substitution

concentration 2 = (287 x 1.6) / 412

Simplification

concentration 2 = 459.2 / 412

Result

concentration 2 = 1.11 M

5 0

3 years ago