How does nuclear fission produce energy answer.com?

2 answers:

7 0

Nuclear energy originates from splitting of uranium atoms a process called fission. This generates heat to produce steam.

Hope this helps❤️

stich3 [128]3 years ago

7 0

Answer:

Nuclear fission is described as a phenomenon that causes an atom to dissociate into smaller atoms, during the split energy is produced.

Explanation:

Nuclear fission can be used as a source of power generation by nuclear plants, but does possess environmental concerns.

You might be interested in

What are three factors that control deep currents?

Lyrx [107]

Global winds, coriolis effect and <span>continental deflections. Hope this helps!</span>

8 0

3 years ago

PLEASE HELP ME ILL GIVE BRAINLIEST IF YOU EXPLAIN UR ANSWER

Marina CMI [18]

The contraction of the triceps muscle causes the arm to flex. The contraction of the triceps muscle causes the arm to extend. When added to the force of the biceps contracting it provides extra force to the ball.

The answer is A

5 0

3 years ago

Read 2 more answers

Suggest a possible

shepuryov [24]

Answer: a reason for this is fossil fuels

Explanation:

The reduction in SO2 is largely due to the implementation of the Acid Rain Program under the Clean Air Act through a cap and trade program for fossil-fuel powered plants.

5 0

3 years ago

While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by

grin007 [14]

Answer:

$n_{C2H_5OH}^{eq}=14.234mol$

Explanation:

Hello,

In this case, the reaction is:

$C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH$

Thus, the law of mass action turns out:

$Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}$

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change $x$ result:

$[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol$

In such a way, the equilibrium constant is then:

$Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31$

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

$Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}} =20.31$