Answer:
127°
Step-by-step explanation:
171+62+127=360
{(3, -1), (7,1), (-6,-1), (9,1), (2,-1)} is the right answer because each input has only one output. (none of the x's repeat).
Answer:
the equation is in form
y=mx+b where
m=slope
and
b=y-int (the y value for the vertex)
first we look to see what the y value is for the point where x=0 and we can see that it is 5 so b=5
then we look at the slope, slope it the amont of units up then to the side are needed to reach the next point, in this case the line goes up 1 then to the right 1 so the slope is 1/1 (1) so the full equation is
y=x+5
Step-by-step explanation:
Keywords
triangle,perimeter,distance, length, side, points
we know that
The <u>perimeter</u> of a<u> triangle</u> is the sum of the three <u>length</u> <u>side</u>
To find the<u> length</u> <u>side</u> calculate the <u>distance</u> between two <u>points</u>
The formula to calculate the <u>distance</u> between to <u>points</u> is equal to
![d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%2B%28x2-x1%29%5E%7B2%7D%7D)
Step 1
Find the <u>distance</u> ZY
substitute the values
![d=\sqrt{(1-0)^{2}+(3-1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%281-0%29%5E%7B2%7D%2B%283-1%29%5E%7B2%7D%7D)
![dZY=\sqrt{5}\ units](https://tex.z-dn.net/?f=dZY%3D%5Csqrt%7B5%7D%5C%20units)
Step 2
Find the <u>distance</u> XY
substitute the values
![d=\sqrt{(1-4)^{2}+(3+1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%281-4%29%5E%7B2%7D%2B%283%2B1%29%5E%7B2%7D%7D)
Step 3
Find the <u>perimeter</u> of the <u>triangle</u>
![P=ZX+ZY+XY](https://tex.z-dn.net/?f=P%3DZX%2BZY%2BXY)
we have
![dZX=2\sqrt{5}\ units](https://tex.z-dn.net/?f=dZX%3D2%5Csqrt%7B5%7D%5C%20units)
![dZY=\sqrt{5}\ units](https://tex.z-dn.net/?f=dZY%3D%5Csqrt%7B5%7D%5C%20units)
Substitute
![P=(2\sqrt{5}+\sqrt{5}+5)\ units](https://tex.z-dn.net/?f=P%3D%282%5Csqrt%7B5%7D%2B%5Csqrt%7B5%7D%2B5%29%5C%20units)
therefore
the answer is
![P=(3\sqrt{5}+5)\ units](https://tex.z-dn.net/?f=P%3D%283%5Csqrt%7B5%7D%2B5%29%5C%20units)
Easiest method you can apply (Cramer's one). <em>"</em><em>Thanks</em><em> </em><em>me</em><em>"</em><em> </em>if i've been helpful