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Artemon [7]
3 years ago
6

What are the solutions of the compound inequality -6<=2x-4<4? Graph the solutions

Mathematics
1 answer:
Nata [24]3 years ago
5 0

-6\leq2x-4 < 4\qquad\text{add 4 to both sides}\\\\-2\leq2x < 8\qquad\text{divide both sides by 2}\\\\-1\leq x < 4

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Express in simplest a+bi form: Square root of 1b + Square root of -1b
Nimfa-mama [501]

Express in simplest a+bi form: Square root of 1b + Square root of -1b

\sqrt{1b} + \sqrt{-1b}

Lets simplify \sqrt{-b}

We know \sqrt{-1} = i

\sqrt{-b} =i\sqrt{b)

We cannot simplify \sqrt{1b}

\sqrt{1b} + \sqrt{-1b}

\sqrt{1b} + i\sqrt{b}

So a + ib form is \sqrt{1b} + i\sqrt{b}


5 0
3 years ago
Can someone answer this question?? ​
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Answer:

don't ask for an explanation. your answer is below.

Step-by-step explanation:

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3 years ago
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sattari [20]

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∫ f(x) dx = x⁵/5 + 3x⁴/4 - 5x³/3

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