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Misha Larkins [42]
3 years ago
9

Pls help me with this :)

Mathematics
1 answer:
Firdavs [7]3 years ago
6 0

Answer:

looks like school work

Step-by-step explanation:

DO IT ON YOUR OWN

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Help me out with this question please mathematic ✏️
Free_Kalibri [48]

Answer:

the second bubble is the answer

Step-by-step explanation:

7 0
3 years ago
How do I solve #9 & #10
olasank [31]
Do you mean the last two? the 9 and 10 are cut off
6 0
3 years ago
Can you help me with this please. Please show your work. Thx in advance
pentagon [3]
That is correct I think it is
4 0
3 years ago
Read 2 more answers
10+5-7=3y<br><br> -10x+5x+5=-15<br><br> 3x+2x-4x+10<br><br> pre algebra 8th grade math
jasenka [17]

Answer:

1) y=8/3=2 2/3   2) x=4    3) x+10

Step-by-step explanation:

1) 10+5-7=3y

Calculate the sum or difference.

8=3y

Swap the sides of the equation.

3y=8

Divide both sides by 3.

y=8/3=2 2/3

2) -10x+5x+5=-15

Collect like terms.

-5x+5=-15

Move the constant to the right-hand side and change the sign.

-5x=-15-5

Calculate the difference.

-5x=-20

Divide both sides by -5.

x=4

3) 3x+2x-4x+10

Collect like terms.

(3+2-4)x+10

Calculate the sum or difference.

1x+10

When the term has a coefficient of 1, it doesn't have to be written.

x+10

Hope this helps :)

5 0
2 years ago
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.&#10;[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
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