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Tema [17]
3 years ago
13

RUE or FALSE: Red hair and freckles is a helpful (good) mutation.

Physics
1 answer:
nignag [31]3 years ago
7 0
True!!!!!!!!!!!!!!!!!!!!!
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A 1.5 kg ball is dropped from a height of 2.Gm. Assuming energy is
Vikki [24]

Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

6 0
2 years ago
12) A horizontal force of 200 N is applied to move a 55-kg cart (initially at rest) across a 10 m level surface. What is the fin
WINSTONCH [101]

Hi there!

We can use the following:

W = ΔKE = F · d

Find the work done on the cart:

W = 200 · 10 = 2000 J

Now, this is equal to the change in kinetic energy of the object. Its initial kinetic energy is 0 J since it starts from rest, so:

2000J = KEf - KEi

KE is given as:

KE = \frac{1}{2}mv^2

2000J = 1/2(55)v²

4000 = 55v²

√(4000/55) = 8.53 m/s

3 0
3 years ago
A scientist must only base his or her conclusions on observable evidence from investigation
Nezavi [6.7K]

is this a true of false cuz if so this it true

8 0
3 years ago
While riding on I-26 towards Columbia, your mother slams on the brakes, to avoid hitting the car in front of her. Both of your b
emmasim [6.3K]

Hi,

Newton's Law of Inertia explains this action because the resistance of the seat belt allows the change in its state of motion. So because the change of speed, your body moves forward but is restricted by the seat belt.

Have a great day!

4 0
3 years ago
A gas undergoes two processes. In the first, the volume remains constant at 0.200 m3 and the pressure increases from 1.00×105 Pa
Alborosie
<h2>The work done = - 2 x 10⁴ J</h2>

Explanation:

In the first case , the volume is kept constant and pressure varies .

In isothermal process  , the work done

W₁ = V x ΔP

here V is the volume of gas and ΔP is the change in pressure

Thus W₁ = 0

Because there is no change in volume , therefore displacement is zero .

In second case pressure is constant , but volume changes

Thus W₂ = P x ΔV

here P is the pressure  and ΔV is the change in volume

Therefore W₂ = 4 x 10⁵ x 5 x 10⁻² = 2 x 10⁴ J

The total work done W = - 2 x 10⁴ J

Because the work done in compression is negative .

7 0
4 years ago
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