Answer:
If the electronegativity difference between bonded atoms are too much high ionic bonds are formed if the electronegativity diference is 0.4 or less than 0.4 non polar covalnet bond formed the difference greater than 0.4 polar covalent bond formed.
Explanation:
Ionic bond:
It is the bond which is formed by the transfer of electron from one atom to the atom of another element.
Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.
For example:
Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.
Covalent bond:
It is formed by the sharing of electron pair between bonded atoms.
The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.
For example:
In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.
Answer:
Nurses must use organic chemistry to determine how the bodies of their patients metabolized glucose, and how the body reacts to it.
Answer:
Inverse proportion occurs when one value increases and the other decreases. For example, more workers on a job would reduce the time to complete the task. They are inversely proportional.
Ok so I got the answer,and I’m confident it’s right.The answer is I=0
Answer:
80mL
Explanation:
Step 1:
Data obtained from the question.
Initial Volume (V1) = 40mL
Initial temperature (T1) = –123°C
Final temperature (T2) = 27°C
Final volume (V2) =..?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
T(K) = T(°C) + 273
Initial temperature (T1) = –123°C =
–123°C + 273 = 150K
Final temperature (T2) = 27°C = 27°C + 273 = 300K
Step 3:
Determination of the final volume.
This can be obtained as follow:
V1/T1 = V2/T2
Initial Volume (V1) = 40mL
Initial temperature (T1) = 150K
Final temperature (T2) = 300
Final volume (V2) =..?
V1/T1 = V2 /T2
40/150 = V2 /300
Cross multiply
150 x V2 = 40 x 300
Divide both side by 150
V2 = (40 x 300) /150
V2 = 80mL
Therefore, the new volume of the gas is 80mL