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qwelly [4]
2 years ago
5

Match the chemical Equation with his correct type

Chemistry
1 answer:
Alex2 years ago
7 0

Answer:

The answer to your question is given below

Explanation:

1. C. 2NaCl + I2 —> 2NaI + Cl2 => C. Single displacement.

From the above equation, we can see that I2 replaces Cl in NaCl to produce NaI. This is simply called a single displacement reaction.

2. E. 2C4H10 + 13O2 —> 8CO2 + 10H2O => E. Combustion.

The above equation shows the burning of Hydrocarbon in the presence of O2. This is simply called Combustion as CO2 and H2O is produced.

3. D 2H2O —> 2H2 + O2 => D. Decomposition.

From the above equation, we can see that a single compound H2O produces two elements H2 and O2. This is simply called a decomposition reaction.

4. A. ZnS + 2HCl —> ZnCl2 + H2S => A. Double Decomposition.

From the above equation, we can see that Cl replaces S in ZnS to produce ZnCl2 and S replaces Cl in HCl to produce H2S. This is simply called double displacement reaction.

5. B. H2 + Br2 —> 2HBr => B. Synthesis.

From the above equation, we can see that two element H2 and Br2 combine to produce a single compound HBr. This is simply called a synthesis reaction.

You might be interested in
1. The solubility of lead(II) chloride at some high temperature is 3.1 x 10-2 M. Find the Ksp of PbCl2 at this temperature.
solniwko [45]

Answer:

1) The solubility product of the lead(II) chloride is 1.2\times 10^{-4}.

2) The solubility of the aluminium hydroxide is 1.6\times 10^{-10} M.

3)The given statement is false.

Explanation:

1)

Solubility of lead chloride = S=3.1\times 10^-2M

PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)

                            S     2S

The solubility product of the lead(II) chloride = K_{sp}

K_{sp}=[Pb^{2+}][Cl^-]^2

K_{sp}=S\times (2S)^2=4S^3=4\times (3.1\times 10^{-2})^3=1.2\times 10^{-4}

The solubility product of the lead(II) chloride is 1.2\times 10^{-4}.

2)

Concentration of aluminium nitrate = 0.000010 M

Concentration of aluminum ion =1\timed 0.000010 M=0.000010 M

Solubility of aluminium hydroxide in aluminum nitrate solution = S

Al(OH)_3(aq)\rightleftharpoons Al^{3+}(aq)+3OH^-(aq)

                            S     3S

The solubility product of the aluminium nitrate = K_{sp}=1.0\times 10^{-33}

K_{sp}=[Al^{3+}][OH^-]^3

1.0\times 10^{-33}=(0.000010+S)\times (3S)^3

S=1.6\times 10^{-10} M

The solubility of the aluminium hydroxide is 1.6\times 10^{-10} M.

3.

Molarity=\frac{Moles}{Volume (L)}

Mass of NaCl= 3.5 mg = 0.0035 g

1 mg = 0.001 g

Moles of NaCl = \frac{0.0035 g}{58.5 g/mol}=6.0\times 10^{-5} mol

Volume of the solution = 0.250 L

[NaCl]=\frac{6.0\times 10^{-5} mol}{0.250 L}=0.00024 M

1 mole of NaCl gives 1 mole of sodium ion and 1 mole of chloride ions.

[Cl^-]=[NaCl]=0.00024 M

Moles of lead (II) nitrate = n

Volume of the solution = 0.250 L

Molarity lead(II) nitrate = 0.12 M

n=0.12 M]\times 0.250 L=0.030 mol

1 mole of lead nitrate gives 1 mole of lead (II) ion and 2 moles of nitrate ions.

[Pb^{2+}]=[Pb(NO_2)_3]=0.030 M

PbCl_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^-(aq)

Solubility of lead(II) chloride = K_{sp}=1.2\times 10^{-4}

Ionic product of the lead chloride in solution :

Q_i=[Pb^{2+}][Cl^-]^2=0.030 M\times (0.00024 M)^2=1.7\times 10^{-9}

Q_i ( no precipitation)

The given statement is false.

3 0
3 years ago
Which element, Sulfur or Chlorine, would have the higher first ionization energy?
Lyrx [107]

Answer:

Chlorine

Explanation:

7 0
3 years ago
Read 2 more answers
An atom of boron has an atomic number of 5 and an atomic mass of 11. the atom contains
kirill [66]
The atom contain 6 neutrons, if that's the question
8 0
3 years ago
The formula for lithium oxide is A) Li2O B) LiO2 C) LiO D) Li2O3
Greeley [361]
Li2O is the formula for <span> lithium oxide</span>
4 0
3 years ago
Read 2 more answers
It is possible to have more than the maximum amount of solute dissolved in a solvent.
vladimir1956 [14]

B. False

When the maximum amount of solute has been dissolved in a given amount of solvent, we say that the solution is saturated with solute.

3 0
3 years ago
Read 2 more answers
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