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Angelina_Jolie [31]

3 years ago

14

Which accurately completes the statement? Conduction involves the transfer of electric charge or due to the movement of particle

s. O thermal energy Olight waves O protons o neutrons

2 answers:

wolverine [178]3 years ago

7 0

Answer:

A: thermal energy

ale4655 [162]3 years ago

5 0

Answer:

A-thermal energy

Explanation:

got it right in the test

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Look at this picture of a frog.

fredd [130]

Answer:

Biosphere

Explanation:

The biosphere consist of all living organisms

6 0

3 years ago

Read 2 more answers

What is the average velocity of a dragster that starts from rest at the starting line and finishes a race at 2600 m/s in 12 seco

xxMikexx [17]

Using the equation v(avg)=distance/time
and the equation v=v(original)+a(t)
solve for acceleration
2600=0+a(12)
a=216.66666 m/s^2

Then, you use the equation
v^2=v(original)+2a*(change in x)
2600^2=2(216.666666)*change in x
6760000/2/216.666666 = 15600 meters which is the length of the race

Then using v(avg)=x/t
15600/12= 1300 m/s

7 0

3 years ago

Imagine you derive the following expression by analyzing the physics of a particular system: v2=v20+2ax. The problem requires so

lisabon 2012 [21]

As per kinematics equation we are given that

$v^2 = v_o^2 + 2ax$

now we are given that

a = 2.55 m/s^2

$v_0 = 21.8 m/s$

$v = 0$

now we need to find x

from above equation we have

$0^2 = 21.8^2 + 2(2.55)x$

$0 = 475.24 + 5.1 x$

$x = 93.2 m$

so it will cover a distance of 93.2 m

7 0

3 years ago

Read 2 more answers

A 12-kg hammer strikes a nail at a velocity of 8.5 m/s and comes to rest in a time interval of 8.0 ms. (A) What is the impulse g

dimulka [17.4K]

Answer:

102 kg.m/s

Explanation:

m = Mass of hammer = 12 kg

v = Final velocity = 8.5 m/s

u = Initial velocity = 0

t = Time taken = 8 ms

Force acting over a given amount of time or change in momentum is known as impulse.

Impulse

$J=Ft\\\Rightarrow J=p_2-p_1\\\Rightarrow J=m(v-u)\\\Rightarrow J=12(8.5-0)\\\Rightarrow J=102\kg.m/s$

Impulse given to the nail is 102 kg.m/s

6 0

3 years ago

Read 2 more answers

A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa

vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

a)

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo = (16.1*25- 160) ft / 5s = 48.5 ft/s

b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

c)

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0

3 years ago