Answer:
he fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true
Explanation:
Let's pose the solution of this problem, to be able to analyze the firm affirmations.
When the person is falling, the weight acts on them all the time, initially the rope has no force, but at the moment it begins to lash it exerts a force towards the top that is proportional to the lengthening of the rope.
The equation for this part is
Fe - W = m a
k x - mg = m a
As the axis of rotation is located at the top where they jump, there is a torque.
What is it
Fe y - W y = I α
angular and linear acceleration are related
a = α r
Fe y - W y = I a / r
In the fall movement we see that both the force is different from zero, and the torque is different from zero.
When analyzing the statements the d is true
Answer:
-4.71 m/s
Explanation:
Given:
y₀ = 1.13 m
y = 0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: v
v² = v₀² + 2a (y − y₀)
v² = (0 m/s)² + 2(-9.8 m/s²) (0 m − 1.13 m)
v = -4.71 m/s
"F=Vector Sum Of The Two Forces" Is the answer.
Answer:
D) The ball exerts a force on the wall and the wall exerts a force back.
Explanation:
Newton's third law of motion states that:
"When an object A exerts a force on another object B, then object B exerts an equal and opposite force on object A"
In this problem, we can identify (for instance) object A with tha ball and object B with the wall. Therefore, if we apply Newton's third law, we get:
The ball (object A) exerts a force on the wall (object B), therefore the wall (object B) exerts an equal and opposite force on the ball (object A). So, option D is the correct one.
