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Lynna [10]
2 years ago
12

12) Photosynthesis is a chemical reaction where carbon dioxide and water react to form glucose (C6H12O6) and oxygen gas. Which r

epresents the proper balanced equations for photosynthesis?
Physics
2 answers:
stich3 [128]2 years ago
7 0

Answer : The balanced chemical reaction will be,

6CO_2+6H_2O\overset{sunlight}\rightarrow C_6H_{12}O_6+6O_2

Explanation :

Photosynthesis : It is a type of chemical process which occurs in the green plants or the living organisms.

During the photosynthesis process, carbon dioxide reacts with the water in the presence of sunlight to gives product as glucose and oxygen.

In this reaction, carbon dioxide and water molecule are the reactants and glucose and oxygen are the products.

The balanced chemical reaction will be,

6CO_2+6H_2O\overset{sunlight}\rightarrow C_6H_{12}O_6+6O_2

denis23 [38]2 years ago
6 0
6CO2 + 6H2O + light energy = C6H12O6 + 6O2.
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The angle of incidence for a ray of light passing through the centre of curvature of a concave mirror is.
evablogger [386]

The angle of incidence for a ray of light passing through the center of curvature of a concave mirror is 0°.

The angle of incidence is the angle between the surface's normal and the incident ray. For a concave mirror, the normal of the surface is along the center of the curvature, and a ray of light passed through a center of curvature passes through the normal of the surface.

The ray of light retreats its path making a zero angle of reflection. The law of reflection state that the angle of incidence is equal to the angle of reflection; therefore, the angle of incidence of a concave surface passed through the center of curvature is zero degrees.

Learn more about the  angle of incidence here:

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8 0
1 year ago
Compare lunar and solar eclipses and answer the following questions:
xeze [42]
So lunar eclips earth between sun and moon
Solar eclips moon between sun and earth.
About the 3th.. im not sure, it depends on if you meen a total solar eclips or not... i think total is more rare then a lunar eclipse..

3 0
3 years ago
An ocean wave has an amplitude of 2.5 m. Weather conditions suddenly change such that the wave has an
Dovator [93]

Answer:

2.5

Explanation:2.5 +2.5 = 5.0

8 0
3 years ago
A 10 kg monkey climbs up a massless rope that runs over a frictionless tree limb and back down to a 15 kg package on the ground.
pshichka [43]

Answer:

A. 4,9 m/s2

B. 2,0 m/s2

C. 120 N

Explanation:

In the image, 1 is going to represent the monkey and 2 is going to be the package.  Let a_mín be the minimum acceleration that the monkey should have in the upward direction, so the package is barely lifted. Apply Newton’s second law of motion:

\sum F_y=m_1*a_m_i_n = T-m_1*g

If the package is barely lifted, that means that T=m_2*g; then:

\sum F_y =m_1*a_m_i_n=m_2*g-m_1*g

Solving the equation for a_mín, we have:

a_m_i_n=((m_2-m_1)/m_1)*g = ((15kg-10kg)/10kg)*9,8 m/s^2 =4,9 m/s^2

Once the monkey stops its climb and holds onto the rope, we set the equation of Newton’s second law as it follows:

For the monkey: \sum F_y = m_1*a \rightarrow T-m_1*g=m_1*a

For the package: \sum F_y = m_2*a \rightarrow m_2*g - T = m_2*a

The acceleration a is the same for both monkey and package, but have opposite directions, this means that when the monkey accelerates upwards, the package does it downwards and vice versa. Therefore, the acceleration a on the equation for the package is negative; however, if we invert the signs on the sum of forces, it has the same effect. To be clearer:

For the package: \sum F_y = -m_2*a \rightarrow T-m2*g=-m_2*a \rightarrow m_2*g -T=m_2 *a

We have two unknowns and two equations, so we can proceed. We can match both tensions and have:

m_1*a+m_1*g=m_2*g-m_2*a

Solving a, we have

(m_1+m_2)*a =(m_2 - m1)*g\\\\a=((m_2-m_1)/(m_1+m_2))*g \rightarrow a=((15kg-10kg)/(10kg+15kg))*9,8 m/s^2\\\\a= 2,0 m/s^2

We can then replace this value of a in one for the sums of force and find the tension T:

T = m_1*a+m_1*g \rightarrow T=m_1*(a+g)\\\\T = 10kg*(2,0 m/s^2+9,8 m/s^2) \\\\T = 120 N

5 0
3 years ago
Two boats start together and race across a 48-km-wide lake and back. Boat A goes across at 48 km/h and returns at 48 km/h. Boat
nika2105 [10]

Answer:

Part 1)

Boat A will win the race

Part 2)

Boat A will win the race by 48 km as the 2nd boat will reach the other end while boat A will just touches the finish line

Part 3)

average velocity must be zero

Explanation:

As we know that the distance moved by the boat is given as

d = 48 km

now the time taken by the boat to move to and fro is given as

t = \frac{d}{v}

t = \frac{48 + 48}{48}

t = 2 hrs

Time taken by Boat B to cover the distance

t = \frac{48}{24} + \frac{48}{72}

t = 2.66 h

Part 1)

Boat A will win the race

Part 2)

Boat A will win the race by 48 km as the 2nd boat will reach the other end while boat A will just touches the finish line

Part 3)

Since the displacement of Boat A is zero

so average velocity must be zero

3 0
3 years ago
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