(a) The equation for the work done in stretching the spring from x1 to x2 is ¹/₂K₂Δx².
(b) The work done, in stretching the spring from x1 to x2 is 11.25 J.
(c) The work, necessary to stretch the spring from x = 0 to x3 is 64.28 J.
<h3>
Work done in the spring</h3>
The work done in stretching the spring is calculated as follows;
W = ¹/₂kx²
W(1 to 2) = ¹/₂K₂Δx²
W(1 to 2) = ¹/₂(250)(0.65 - 0.35)²
W(1 to 2) = 11.25 J
W(0 to 3) = ¹/₂k₁x₁² + ¹/₂k₂x₂² + ¹/₂F₃x₃
W(0 to 3) = ¹/₂(660)(0.35)² + ¹/₂(250)(0.65 - 0.35)² + ¹/₂(105)(0.89 - 0.65)
W(0 to 3) = 64.28 J
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Velocity is defined as a change in position.
You would get a wrong calculaton which if you are doing an experiment it can mess with the results
Black hole
hope it helped
Answer:
Explanation:
mass, m = 12 kg
Force, F = 40 N
θ = 37° below the horizontal
(a)
Diagram is attached
(b) Let N be the normal reaction
According to the diagram
N + F Sin θ = m g
N = mg - F Sin θ
N = 12 x 9.8 - 40 x Sin 37
N = 117.6 - 24.07
N = 93.53
