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2 years ago

Please please please please please please help me a b c or d

Chemistry

1 answer:

otez555 [7]2 years ago

6 0

Answer:

how far an object moves in a certain amount of time

Explanation:

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A car traveling at a speed of 30.0 m/s encounters an emergency and comes to a complete stop in 7.5 seconds? What is the cars acc

Marianna [84]

Answer:

The acceleration is: $4m/s^2$

Explanation:

Given

$u = 30.0m/s$ --- The initial velocity

$t = 7.5s$ --- time

$v = 0m/s$ -- The final velocity

Required

Determine the acceleration

To do this, we make use of the first equation of motion

$v = u - at$

We used negative because the car was coming to stop.

This gives:

$0 = 30 - 7.5 * a$

$0 = 30 - 7.5a$

Collect like terms

$7.5a = 30$

Solve for a

$a = \frac{30}{7.5}$

$a = 4m/s^2$

6 0

2 years ago

Calculate the amount in grams of Na2CO3 needed in a reaction with HCl to produce 120g NaCl?

klemol [59]

The balanced chemical reaction is written as :

Na2CO3<span> + 2HCl === 2NaCl + H2O + CO2
</span>
We are given the amount of NaCl to be produced from the reaction. This will be the starting point for the calculations. We do as follows:

120 g NaCl ( 1 mol / 58.44 g) ( 1 mol Na2CO3 / 2 mol NaCl)( 105.99 g / 1 mol ) = 1108.82 g Na2CO3 needed

8 0

2 years ago

For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.

Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0

2 years ago

The solubility product constant of pbcl2 is 1.7 × 10−5 . what is the maximum concentration of pb2+ that can be in ocean water th

Sunny_sXe [5.5K]

Answer is: the maximum concentration of Pb²⁺ is 6.8·10⁻³ M.
Chemical reaction 1: PbCl₂(s) → Pb²⁺(aq) + 2Cl⁻(aq).
Chemical reaction 2: NaCl(aq) → Na⁺(aq) + Cl⁻(aq).
Ksp(PbCl₂) = 1.7·10⁻⁵.
c(NaCl) = c(Cl⁻) = 0.0500 M.
Ksp(PbCl₂) = c(Pb²⁺) · c(Cl⁻)².
c(Pb²⁺) = Ksp(PbCl₂) ÷ c(Cl⁻)².
c(Pb²⁺) = 1.7·10⁻⁵ M³ ÷ (0.0500 M)².
c(Pb²⁺) = 0.000017 M³ ÷ 0.0025 M².
c(Pb²⁺) = 0.0068 M = 6.8·10⁻³ M.

3 0

2 years ago

Please help I will mark brainy

Artyom0805 [142]

Answer:

the answer is c I took the test

3 0

2 years ago