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Kay [80]
2 years ago
13

How do chemists model the valence electrons in a metal

Chemistry
1 answer:
Bumek [7]2 years ago
5 0

Answer:

the valence electrons of atoms in a pure metal can be modeled as a sea of electrons

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3. A helium laser emits light with a wavelength of 6.33 x 10^-7m. What is
HACTEHA [7]

Answer:

4.52 x 10¹⁴ cycles/s

Explanation:

From c = f·λ => f = c/λ = (3.0 x 10⁸ m/s)/(6.63 x 10⁻⁷m) = 4.52 x 10¹⁴ cycles/s.

f = frequency = ?

λ = wavelength = 6.63 x 10⁻⁷ meter

c = speed of light in vacuum = 3.0 x 10⁸ meters/s

7 0
2 years ago
Where in the mitochondria does the electron transport chain occur
wolverine [178]
I think it’s the inner membrane
6 0
2 years ago
If a chemical reaction occurs in a direction that has a positive change in entropy thenGroup of answer choicesthe change in enth
mezya [45]

Answer:

The reaction must be spontaneous, the disorder of the system increases.

Explanation:

By the Second Law of Thermodynamics, a positive change in entropy is due to a net input heat, and entropy is a measure of the grade of disorder within the system. The net input heat means that resultant goes to the system from the surroundings.

By the First Law of Thermodynamics, a net input heat is due to a positive change in enthalpy.

The reaction is endothermic and spontaneous (since change in entropy is positive).

6 0
3 years ago
Anyone help plz <br> And ty
andreyandreev [35.5K]

Answer: do that yourself dip

Explanation:

6 0
3 years ago
What is the Ka of a weak acid (HA) if the initial concentration of weak acid is 4.5 x 10-4 M and the pH is 6.87? (pick one)
rewona [7]

Answer:

Ka = 4.04 \times 10^{-11}

Explanation:

Initial concentration of weak acid = 4.5 \times 10^{-4}\ M

pH = 6.87

pH = -log[H^+]

[H^+]=10^{-pH}

[H^+]=10^{-6.87}=1.35 \times 10^{-7}\ M

HA dissociated as:

HA \leftrightharpoons H^+ + A^{-}

(0.00045 - x)    x     x

[HA] at equilibrium = (0.00045 - x) M

x = 1.35 \times 10^{-7}\ M

Ka = \frac{[H^+][A^{-}]}{[HA]}

Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 - 0.000000135}

0.000000135 <<< 0.00045

Therefore, Ka = \frac{(1.35 \times 10^{-7})^2}{0.00045 } = 4.04 \times 10^{-11}

5 0
3 years ago
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