1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
2 years ago
10

Explain the difference between a polar bond and a polar molecule.

Chemistry
1 answer:
NeTakaya2 years ago
7 0
A polar bond is when the charge distribution between two atoms is unequal whereas in a polar molecule the charge distribution is not symmetric
You might be interested in
Which of the following is a cause of a dna mutation
lisov135 [29]

Answer:

Can you please tell us what the following are?

5 0
3 years ago
How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
nikdorinn [45]

You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

O (3) = 16 (3) g

Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

8 0
3 years ago
How many protons, neutrons, and electrons are in Uranium-232? How many protons, neutrons, and electrons are in Uranium-232?
QveST [7]

Protons/Electrons: 92

Neutrons: 140

***REMEMBER: There is always the same amount of protons and electrons. :)

7 0
3 years ago
What percentage of radioactive substance remains after two half-lives
Ksju [112]

Answer:

After 2 half-lives there will be 25% of the original isotope, and 75% of the decay product. After 3 half-lives there will be 12.5% of the original isotope, and 87.5% of the decay product. After 4 half-lives there will be 6.25% of the original isotope, and 93.75% of the decay product.

Explanation:

3 0
2 years ago
To determine the limiting reactant in a chemical reaction, one must know the:.
sveticcg [70]

Answer:

The available amounts of each reactant

Explanation:

The limiting reactant is the reactant that will limit the equation.

For example, I have 2N2 and H2O. In this situation, H2O would be the limiting reactant since there is only one atom, while N2 has two atoms.

Think of it like you're making peanut butter and jelly. You have 50 cans of peanut butter and only 10 jelly. Which means you can only make sandwiches using 10 jars of jelly and 10 jars of peanut butter.

4 0
2 years ago
Other questions:
  • How is oxygen separated from other substances nearby?
    11·1 answer
  • How many moles are in 1.84x10^24 formula units of CaCl2, calcium chloride?
    9·1 answer
  • What mass of water can be obtained from 4.0 g of H2 and 16 g of O2?
    5·1 answer
  • In one compound of lead and sulfur, there are 6.46 g of lead
    13·1 answer
  • What are valence electrons?
    6·1 answer
  • A compound decomposes by a first-order process. If 37 % of the compound decomposes in 60 minutes, the half-life of the compound
    14·1 answer
  • How can scientific themes apply to many branches of science?
    7·2 answers
  • If 7.50 g of methane gas (CH4) is in a 3250 mL container at 25° C, what is the pressure
    9·1 answer
  • Which of the following statements is true about what happens in all chemical reactions? A. The ways in which atoms are joined to
    6·1 answer
  • Which of the following is NOT an advantage of a wireless network? convenience reliability security speed
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!