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DaniilM [7]
3 years ago
9

What single condition is required to insure that a molecule will be polar covalent?

Chemistry
1 answer:
KiRa [710]3 years ago
5 0

Answer:

(B) A bond between atoms that are different in electronegativity.

Explanation:

If the atoms have different electronegativities, one atom will have greater electron density than the other. The bond will be polar.

(A) is wrong. Atomic mass does not affect electronegativity.

(C) is wrong. If the two atoms are alike, the bond is pure covalent.

You might be interested in
how many moles of a nonvolatile, nonelectrolyte solute are required to lower the freezing point of 1000 grams of water by 5.58
Ivan

Answer:

Explanation:

Using freezing point depression formula,

ΔTemp.f = Kf * b * i

Where,

ΔTemp.f = temp.f(pure solvent) - temp.f(solution)

b = molality

i = van't Hoff factor

Kf = cryoscopic constant

= 1.86°C/m for water

= (0 - (-5.58))/1.86

= 3.00 mol/kg

Assume 1 kg of water(solvent)

= (3.00 x 1)

= 3.00 mol.

5 0
3 years ago
How glass tube filed with acidified potassium dichromate detect drunken driver
hodyreva [135]

Answer:

See explanation

Explanation:

The reaction between alcohol and acidified potassium dichromate  is a redox reaction. This reaction can be used to detect a drunken driver.

Alcohols can be oxidized to aldehydes, ketones and carboxylic acids depending on the structure of the alcohol. Primary alcohols yield adehydes and carboxylic acids while secondary alcohols are oxidized to ketones.

The colour of the acidified potassium dichromate turns from orange to green when exposed to alcohols from the breath of a drunken driver.

5 0
3 years ago
23) What is the volume of 2.454 x 1024 atoms of nitrogen gas at STP?
earnstyle [38]

Answer:

d) V =  91.3 L

Explanation:

Given data:

Volume of nitrogen = ?

Temperature = standard = 273.15 K

Pressure = standard = 1 atm

Number of atoms of nitrogen = 2.454×10²⁴ atoms

Solution:

First of all we will calculate the number of moles of nitrogen by using Avogadro number.

1 mole = 6.022×10²³ atoms

2.454×10²⁴ atoms × 1 mol / 6.022×10²³ atoms

0.407×10¹ mol

4.07 mol

Volume of nitrogen:

PV = nRT

1 atm × V = 4.07 mol ×0.0821 atm.L /mol.K ×273.15 K

V =  91.3 atm.L /1 atm

V =  91.3 L

3 0
3 years ago
HELP ME PLEASE I NEED THE ANDEER NOW
AysviL [449]
The answer is 0.430 .
8 0
3 years ago
Correct?
erica [24]
Correct answer is C

Na2O + H2O ----> 2 NaOH

:-) ;-)
4 0
3 years ago
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