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Mariana [72]
3 years ago
7

Types of government

Physics
2 answers:
zloy xaker [14]3 years ago
4 0
Direct democracy a representative democracy,socialism,communism,a monarchy,an oligarchy and an autocracy
igor_vitrenko [27]3 years ago
3 0

Answer:

Explanation:

The different types of government include a direct democracy, a representative democracy, socialism, communism, a monarchy, an oligarchy, and an autocracy

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As a laudably skeptical physics student, you want to test Coulomb's law. For this purpose, you set up a measurement in which a p
coldgirl [10]

Answer:

Explanation:

charge, q = 1.6 x 10^-19 C

distance, r = 911 nm = 911 x 10^-9 m

The Coulomb's force is given by

F=\frac{Kq_{1}q_{2}}{r^{2}}

F=\frac{9\times 10^{9}\times 1.6\times 10^{-19}\times 1.6\times 10^{-19}}{\left (911\times 10^{-9}  \right )^2}

F = 2.78 x 10^-16 N

The force between the electron and the proton is 2.78 x 10^-16 N.

4 0
3 years ago
A salt is dissolved in water which has a freezing point of 0 degrees celsius. the freezing point of the solution would be
balandron [24]
A salt is dissolved in water which has a freezing point of 0 degrees celsius. the freezing point of the solution would be dependent on the concentration of the salt in the solution. It is explained by the colligative properties. These <span>are </span>properties<span> that depend upon the concentration of solute molecules or ions, but not upon the identity of the solute. Hope this answers the question.</span>
7 0
3 years ago
Read 2 more answers
A magnetically soft material is placed in a strong magnetic field. What is the most likely outcome?
Svet_ta [14]

D-It will become a temporary magnet because the domains will easily realign.

9 0
3 years ago
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A hollow cylinder of mass 2.00 kg, inner radius 0.100 m, and outer radius 0.200 m is free to rotate without friction around a ho
Aneli [31]

Answer:

h=2.86m

Explanation:

In order to give a quick response to this exercise we will use the equations of conservation of kinetic and potential energy, the equation is given by,

\Delta PE_i + \Delta KE_i = \Delta PE_f +\Delta KE_f

There is no kinetic energy in the initial state, nor potential energy in the end,

mgh+0=0+KE_f

In the final kinetic energy, the energy contributed by the Inertia must be considered, as well,

mgh = (\frac{1}{2}mv^2+\frac{1}{2}I\omega^2)

The inertia of the bodies is given by the equation,

I=\frac{m(R_1^2+R^2_2)}{2}

I=\frac{2(0.2^2+0.1^2)}{2}

I=0.05Kgm^2

On the other hand the angular velocity is given by

\omega =\frac{v}{R_2}=\frac{4}{1/5} = 2rad/s

Replacing these values in the equation,

(0.5)(9.8)(h) =\frac{1}{2}*0.5*4^2+\frac{1}{2}*0.05*20^2

Solving for h,

h=2.86m

5 0
3 years ago
A 1 200-kg car traveling initially at vCi 5 25.0 m/s in an easterly direction crashes into the back of a 9 000-kg truck moving i
sukhopar [10]

Answer:

The velocity of the truck after the collision is 20.93 m/s

Explanation:

It is given that,

Mass of car, m₁ = 1200 kg

Initial velocity of the car, v_{Ci}=25\ m/s

Mass of truck, m₂ = 9000 kg

Initial velocity of the truck, v_{Ti}=20\ m/s

After the collision, velocity of the car, v_{Cf}=18\ m/s

Let v is the velocity of the truck immediately after the collision. The momentum of the system remains conversed.

initial\ momentum=final\ momentum

1200\ kg\times 25\ m/s+9000\ kg\times 20\ m/s=1200\ kg\times 18+9000\ kg\times v

210000-21600=9000\ kg\times v

v=20.93\ m/s

So, the velocity of the truck after the collision is 20.93 m/s. Hence, this is the required solution.

8 0
3 years ago
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