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mojhsa [17]
4 years ago
9

An object is constrained by a cord to move in a circular path of radius 1-m on a frictionless, horizontal surface. The cord will

break if the tension exceeds 26.9-N. The maximum kinetic energy that this object can have is _____ J. Round your answer to the nearest whole number.
Physics
1 answer:
katovenus [111]4 years ago
6 0

Answer:

Explanation:

Let m be the mass of the object and v be the maximum velocity . The tension will provide centripetal force for the circular motion .

T = mv² / R where R is radius of circular path . T is tension .

putting the values given in the equation above

26.9 = m v² / 1

m v² = 26.9

kinetic enrgy = 1/2 m v²

= 26.9 / 2

= 13.45 J

13 J .

Maximum kinetic energy = 13 J .

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