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3 years ago

Help me please!! i’m really confused!!

Mathematics

1 answer:

igomit [66]3 years ago

3 0

Answer:

382

Step-by-step explanation:

Well we need to find surface area.

The formula to find the surface area of a rectangular prism is 2(wl+hl+hw).

Plus everything from width and height and all that stuff in, solve the eqaution.

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I'm not sure how to do these, slader is no assistance to me.

ki77a [65]

Answer:

Perimeter: 18 ft

Height: 7 ft

Base Area: 12

Surface Area: (7)*(8) + 2(47) = 150

Step-by-step explanation:

To find the perimeter add all the edges together.

5 + 5 + 8 = 18

To find the height look at the diagram. 7ft shows the height of the rectangle and thus is the height for the rest of the shape.

Base Area:

Multiply the length (8ft) of the base by the height of the base (3ft)

8 * 3 = 24

Then divide by 2 to get the total area of the triangle

24 / 2 = 12.

Surface Area:

To find the surface area you to need to find the specifics of each side.

The base area we already solved for which is 12. We'll get back to this in a minute. The other double sides are of 5 * 7. That equals 35. Add together 12 + 35 to get 47. That is what will go in the 2(___) box because both of those sides have 2. It is the same number when done this way versus just adding them up.

47 * 2 = 94

12 + 12 + 35 + 35 = 94

Then for the (___)(___) that would be 7ft * 8ft because it is the only side left and does not have a double so it must be separate.

7 * 8 = 56

56+94 = 150

5 0

3 years ago

Read 2 more answers

The graph of a quadratic function intercepts the x-axis in two places and the y-axis in one place.

solmaris [256]

The true statement about the quadratic function is that it has two distinct real zeros

<h3>How to interpret the quadratic function?</h3>

The given parameters are:

x-intercepts = 2 i.e. intercepts the x-axis in two places
y-intercept = 1 i.e. intercepts the y-axis in one place

The first highlight above means that, the function can be represented as:

y = a(x - x1)(x -x2)

Where x1 and x2 are the x-intercepts

This also means that the quadratic function has two distinct real zeros

Read more about quadratic functions at:

brainly.com/question/7323175

#SPJ1

4 0

2 years ago

I need help please if you can help I will give you 10 points

valentina_108 [34]

Answer:

option A

Step-by-step explanation:

7 0

3 years ago

The sides of a right triangle measure 6 times the square root of 3, 6 inches, and 12 inches. If an altitude is drawn from the ri

VARVARA [1.3K]

Length of segment of the hypotenuse adjacent to the shorter leg is 5 inches and the length of the altitude is 3 inches.

Step-by-step explanation:

Step 1: Let the triangle be ΔABC with right angle at B. The altitude drawn from B intersects the hypotenuse AC at D. So 2 new right angled triangles are formed, ΔADB and ΔCDB.

Step 2: According to a theorem in similarity of triangles, when an altitude is drawn from any angle to the hypotenuse of a right triangle, the 2 newly formed triangles are similar to each other as well as to the bigger right triangle. So ΔABC ~ ΔADB ~ ΔCDB.

Step 3: Identify the corresponding sides and form an equation based on proportion. Let the length of the altitude be x. Considering ΔABC and ΔADB, AB/DB = AC/AB

⇒ 6/x = 12/6

⇒ 6/x = 2

⇒ x = 3 inches

Step 4: To find length of the hypotenuse adjacent to the shorter leg (side AB of 6 inches), consider ΔADB.

⇒ $AD^{2} + BD^{2} = AB^{2}$

⇒ $AD^{2} =AB^{2} - BD^{2}$

⇒ $AD^{2} =6^{2} -3^{2}$

⇒ $AD^{2} =36 - 9 = 25$

⇒ $AD = \sqrt{25}$

⇒AD = 5 inches

6 0

3 years ago

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and

storchak [24]

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of <u>proportionality</u>, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

$\frac{6.4^{2}}{156} k = 800$

$k=\frac{800.156}{96}$

k = 1300

For the similar beam:

$\frac{8.7^{2}}{L}1300=1300$

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

6 0

3 years ago