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vaieri [72.5K]
3 years ago
10

Who ever gets this will gets this right will get a brainlest and a good rating

Mathematics
2 answers:
lara31 [8.8K]3 years ago
6 0

Answer:

The couch should be priced at 163.85

Step-by-step explanation:

multiply the wholesale price by %145

Tema [17]3 years ago
4 0

Answer:

163.85

Step-by-step explanation:

113.00+50.85=163.85.

50.85 is 45% of 113.00

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X÷2=6<br><br>need help<br><br>Alguem me ajuda<br><br>necesito ayuda​
Ganezh [65]
Divide both sides by 2

X=3
8 0
3 years ago
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Analyze the graph h(x).
Dominik [7]

Answer:

D h(x) = f(x)×g(x)

Step-by-step explanation:

h(x) has a wave with 2 changes in direction.

so, this needs to be an expression of the third degree (there must be a term with x³ as the highest power of x).

and that is only possible when multiplying both basic functions. all the other options would keep it at second degree (x²) or render it even to a first degree (linear).

8 0
3 years ago
Factor the expression over the complex numbers.<br><br> x2+50
Leto [7]

  x² + 50

= x² - (-50)

= \sqrt{x^{2} } +/- \sqrt{-50}            Side note: \sqrt{-50} = \sqrt{(-1) * 5 * 5} = 5i

= (x + 5i)(x - 5i)

8 0
4 years ago
Read 2 more answers
How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
What is the value of x???
svetoff [14.1K]
I do believe it would be x=30
3 0
3 years ago
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