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ohaa [14]
3 years ago
7

a man walked for some distance at 8 km /h and for an equal distance at 5km/h. the total time he took was 3 whole number 1/4 hour

s. find the total distance he walked.
Mathematics
1 answer:
slega [8]3 years ago
5 0

Answer:

the total distance walked is 20 km

Step-by-step explanation:

The computation of the total distance he walked is shown below:

Let us assume the total distance walked be d

Now the total time would be

Total time = (d ÷ 2) ÷ 8 +  (d ÷ 2) ÷ 5 = 3.25

d ÷ 16 + d ÷ 10 = 3.25

(5d + 8d) ÷ 80=3.25

13d = 260

d = 20 km

Hence, the total distance walked is 20 km

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Select the answer choices that show two fractions that are equal. (Select two)..
Kruka [31]

Problem 1

Answers: Choice A, choice D

The formula you use is

a & c/d = (a*d+c)/d

To convert from mixed number form to improper fraction form.

So,

6 & 2/3 = (6*3+2)/3 = (18+2)/3 = 20/3

And also,

8 & 1/5 = (8*5+1)/5 = (40+1)/5 = 41/5

===============================================

Problem 2

Answer: Reflection

Think of how mirrors cause a reflection and this should help you remember the term better. If we reflect point A over some line L, to get point A', then the distance from A to L is the same from A' to L also.

5 0
3 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acce
storchak [24]

Answer:

The correct answer will be "60 min/hour".

Step-by-step explanation:

At time 2:00 PM

A car reads = 30 mi/h

At time 2:20 PM

A car reads = 50 mi/h

Now,

At time 2:00 PM

t = 0

At time 2:20 PM

t = \frac{1}{3}

v(0)=30

v(\frac{1}{3})=50

For MVT,

v'(c)=\frac{v(\frac{1}{3} -v(0))}{(\frac{1}{3} )}

       =\frac{20}{\frac{1}{3} }

       =60 \ min/hour

5 0
3 years ago
I'LL GIVE BRAINLIEST !!! FASTER<br><br>please explain how do you get the answer !​
aliya0001 [1]

Answer:

70

Step-by-step explanation:

we have the angle of vertex in the isosceles triangle = 180-2*bottom coner= 180-65/2=50

3 angles in the equilateral triangle are equal to 60

we have 50 + 60 +h =the angle of PQR =180

h=70

7 0
3 years ago
Read 2 more answers
Need answer quick
Stells [14]

The answer would be B 42 miles.

3 0
3 years ago
Read 2 more answers
Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=
Ganezh [65]

Answer:

y(1+x)+x-5\ln xy=C

Step-by-step explanation:

Consider the given differential equation is

(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1

(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y

(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx

Taking all variables on right sides.

(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0

(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0

Let as assume,

M=-\frac{5}{x}+1+y and N=1-\frac{5}{y}+x

Find partial derivatives \frac{\partial M}{\partial y} and \frac{\partial N}{\partial x}

\frac{\partial M}{\partial y}=1 and \frac{\partial N}{\partial x}=1

Since \frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}, therefore the given differential equation is exact.

The solution of the exact differential equation is

\int Mdx+\int N(\text{without x)}dy=C

\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C

yx-5\ln x+x+y-5\ln y=C

y+x+xy-5\ln x-5\ln y=C

y(1+x)+x-5(\ln x+\ln y)=C

y(1+x)+x-5\ln xy=C

7 0
4 years ago
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