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miss Akunina [59]
3 years ago
14

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
1 answer:
levacccp [35]3 years ago
7 0
Where’s the picture i need to see it to hel
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A square box has an area of 90,000 square inches. What's the length of each side of the box?
Sever21 [200]

Answer: A 300 inches

Step-by-step explanation:

Area (a) = 90,000

Side = √a

Side = √90000

Side = 300

8 0
3 years ago
Read 2 more answers
Add (13x – 4) and (–6x + 15)
kompoz [17]

(13x – 4) + (–6x + 15) =

13x - 4 - 6x + 15 =

7x + 11

4 0
3 years ago
Hey could someone please help me with this really hard assignment is taking me forever. Thank you marking brainliest!
rewona [7]

Answer:

Exercise 1: The length of the unknown leg is 4 inches.

Exercise 3: The following straws can be used to construct the triangle: b) 3\,in, c) 4.5\,in, d) 6.5\,in, e) 10\,in, f) 13.5\,in

Exercise 4: Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

Step-by-step explanation:

Exercise 1:

Let suppose that triangle represented in the figure is a right triangle, the length of the missing leg is determined by Pythagorean Theorem:

y = \sqrt{l^{2}-x^{2}} (1)

Where:

l - Hypotenuse, in inches.

x - Known leg, in inches.

y - Unknown leg, in inches.

If we know that l = 11\,in and x = 10\,in, then the length of the unknown leg is:

y = \sqrt{21}

Since 4 is the least whole number closest to \sqrt{21}, then we conclude that the length of the unknown leg is 4 inches.

Exercise 3:

The range of possible lengths for the missing side of the triangle is represented by the following simultaneous inequality:

x + y > l > x-y (2)

Where:

x - Greater side, in inches.

y - Lesser side, in inches.

l - Missing side, in inches.

If we know that x = 8\,in and y = 6\,in, then we have the following range of missing sides:

14\,in > l > 2\,in

The following straws can be used to construct the triangle: b) 3\,in, c) 4.5\,in, d) 6.5\,in, e) 10\,in, f) 13.5\,in

Exercise 4:

Let check each pair to determine possible constructions by means of the inequality used in Exercise 3:

(i) x = 4\,in, y = 2\,in

6\,in>l>2\,in

Possible choices: 5 inches.

(ii) x = 5\,in, y = 2\,in

7\,in > l > 3\,in

Possible choices: 4 inches, 6 inches.

(iii) x = 6\,in, y = 2\,in

8\,in > l > 4\,in

Possible choices: 5 inches, 6 inches.

(iv) x = 10\,in, y = 2\,in

12\,in > l > 8\,in

Possible choices: None.

(v) x = 5\,in, y = 4\,in

9\,in > l > 1\,in

Possible choices: 2 inches, 6 inches.

(vi) x = 6\,in, y = 4\,in

10\,in > l > 2\,in

Possible choices: 5 inches.

(vii) x = 10\,in, y = 4\,in

14\,in > l > 6\,in

Possible choices: None.

(viii) x = 6\,in, y = 5\,in

11\,in > l > 1\,in

Possible choices: 2 inches, 4 inches, 10 inches.

(ix) x = 10\,in, y = 5\,in

15\,in > l > 5\,in

Possible choices: 6 inches.

(x) x = 10\,in, y = 6\,in

16\,in > l > 4\,in

Possible choices: 5 inches.

Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

7 0
2 years ago
Read 2 more answers
The population of a town increased by 10% per year in 2009, 2010, and 2011. If the population of the town at the beginning of 20
Bogdan [553]
If the population was 40,000 at the beginning of 2009, at the end of 2009 it has increased by 10% and became 44,000.

By the same way, at the end of 2010, it became 44000 + \frac{44000*10}{100} = 48400

At the end of 2011, the population was 48400 +  \frac{48400 * 10}{100} = 53240 
4 0
3 years ago
Hey can you please help me out posted picture
abruzzese [7]
We have for this case:
 For each language we have:
 Number of people who speak Spanish:
 Spanish = 8 + 4 = 12
 Number of people who speak Chinese:
 Chinese = 5 + 6 = 11
 Number of people who speak both languages:
 Both = 3 + 2 = 5
 Adding we have:
 12 + 11 + 5 = 28
 Answer:
 28
 option A
7 0
3 years ago
Read 2 more answers
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