p= 1/7
Alright, so first, you need to flip the equation.<span><span>It will turn into p+<span>4/7</span></span>=<span>5/7
Next, you want to get the variable by itself so you need to subtract 4/7 from both sides. 5/7-4/7=1/7
p=1/7</span></span>
The answer i x=4/99 (fraction form )
Answer:
The Pythagorean identity states that
![\sin^2 t + \cos^2 t = 1](https://tex.z-dn.net/?f=%5Csin%5E2%20t%20%2B%20%5Ccos%5E2%20t%20%3D%201)
Using that we can rewrite the left denominator as:
![1 - \sin^2 t](https://tex.z-dn.net/?f=1%20-%20%5Csin%5E2%20t)
Which can be factored as
![(1 - \sin t)(1+ \sin t)](https://tex.z-dn.net/?f=%281%20-%20%5Csin%20t%29%281%2B%20%5Csin%20t%29)
The numerator we can expand as:
![(1 - \sin t)(1 - \sin t)](https://tex.z-dn.net/?f=%281%20-%20%5Csin%20t%29%281%20-%20%5Csin%20t%29)
On the right hand side, let's multply numerator and denominator with (1 - sin t):
The total formula then becomes:
![\dfrac{(1-\sin t)(1-\sin t)}{(1 - \sin t)(1 + \sin t)} = \dfrac{(1-\sin t)(1 - \sin t)}{(1+\sin t)(1 - \sin t)}](https://tex.z-dn.net/?f=%5Cdfrac%7B%281-%5Csin%20t%29%281-%5Csin%20t%29%7D%7B%281%20-%20%5Csin%20t%29%281%20%2B%20%5Csin%20t%29%7D%20%3D%20%5Cdfrac%7B%281-%5Csin%20t%29%281%20-%20%5Csin%20t%29%7D%7B%281%2B%5Csin%20t%29%281%20-%20%5Csin%20t%29%7D)
There you go... left and right are equal.
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Answer:
About 15%
Step-by-step explanation:
3 divided by 19 is 0.1578947368421053
0.1578947368421053 multiplied by 100 is 15.78947368421053.