3. What is a caliber (relate it to rockets)
1 answer:
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Answer:
COP = 3.828
W' = 39.18 Kw
Explanation:
From the table A-11 i attached, we can find the entropy for the state 1 at -20°C.
h1 = 238.43 KJ/Kg
s1 = 0.94575 KJ/Kg.K
From table A-12 attached we can do the same for states 3 and 4 but just enthalpy at 800 KPa.
h3 = h4 = hf = 95.47 KJ/Kg
For state 2, we can calculate the enthalpy from table A-13 attached using interpolation at 800 KPa and the condition s2 = s1. We have;
h2 = 275.75 KJ/Kg
The power would be determined from the energy balance in state 1-2 where the mass flow rate will be expressed through the energy balance in state 4-1.
W' = m'(h2 - h1)
W' = Q'_L((h2 - h1)/(h1 - h4))
Where Q'_L = 150 kW
Plugging in the relevant values, we have;
W' = 150((275.75 - 238.43)/(238.43 - 95.47))
W' = 39.18 Kw
Formula foe COP is;
COP = Q'_L/W'
COP = 150/39.18
COP = 3.828
Answer:
present cost = $302218.15
Explanation:
given data
cost of the work 1st year A1 = $100,000
cost of the work 2nd year A2 = $85,000
cost of the work 3rd year A3 = $70,000
cost of the work 4th year A4 = $55,000
cost of the work 5th year A4 = $40,000
interest rate r = 6% = 0.06
to find out
present worth cost is for the first 5 years
solution
present worth cost will be here as per given equation
present cost = .........................1
here r is rate of interest and A is amount given
put here value we get
present cost =
present cost = $302218.15