Answer:
80.7lbft/hr
Explanation:
Flow rate of water in the system = 3.6x10^-6
The height h = 100
1s = 1/3600h
This implies that
Q = 3.6x10^-6/[1/3600]
Q = 0.0000036/0.000278
Q = 0.01295
Then the power is given as
P = rQh
The specific weight of water = 62.3 lb/ft³
P = 62.3 x 0.01295 x 100
P = 80.675lbft/h
When approximated
P = 80.7 lbft/h
This is the average power that could be generated in a year.
This answers the question and also corresponds with the answer in the question.
If a clock frequency is applied to a cascaded counter, The lowest output frequency available will be
- The lowest output frequency will be =
<h3>
Cascade Counter</h3>
For a cascade counter,
Overall frequency = 
Overall frequency = 
<h3>Lowest F
requency</h3>
Therefore,
the lowest frequency
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