Answer:
222.5 Gpa
Explanation:
From definition of engineering stress,
where F is applied force and A is original area
Also, engineering strain, where l is original area and
is elongation
We also know that Hooke's law states that
Since A=20 mm* 20 mm= 0.02 m*0.02 m
F= 89000 N
l= 100 mm= 0.1 m
By substitution we obtain
Answer:
Explanation:
Given that:
The direction of the applied tensile stress =[001]
direction of the slip plane = [01]
normal to the slip plane = [111]
Now, the first thing to do is to calculate the angle between the tensile stress and the slip by using the formula:
where;
= directional indices for tensile stress
= slip direction
replacing their values;
i.e = 0 ,
= 0
= 1 &
= -1 ,
= 0 ,
= 1
Also, to find the angle between the stress [001] & normal slip plane [111]
Then;
replacing their values;
i.e = 0 ,
= 0
= 1 &
= 1 ,
= 1 ,
= 1
However, the critical resolved SS(shear stress) can be computed using the formula:
where;
applied tensile stress 13.9 MPa
∴