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3 years ago

7

Verify the below velocity distribution describes a fluid in a state of pure rotation. What is the angular Velocity? (a)-Vx = -1/

2bx (b)-Vy = -1/2by (c)-Vz = bz

1 answer:

denpristay [2]3 years ago

7 0

Answer:

Angular velocity of fluid is zero.

Explanation:

Given that

$V_x=\dfrac{1}{2}bx$

$V_y=\dfrac{1}{2}by$

$V_z=-bz$

The angular velocity in Z direction

$\omega _z=0.5\times\left (\dfrac{\partial V_y}{\partial x}-\dfrac{\partial V_x}{\partial y} \right )$

$V_x=\dfrac{1}{2}bx$

$\dfrac{\partial V_y}{\partial x}=0$

$V_y=\dfrac{1}{2}by$

$\dfrac{\partial V_x}{\partial y}=0$

So

$\omega _z=0$

Similarly

$\omega _y=0.5\times\left (\dfrac{\partial V_z}{\partial x}-\dfrac{\partial V_x}{\partial z} \right )$

$\omega _x=0.5\times\left (\dfrac{\partial V_z}{\partial y}-\dfrac{\partial V_y}{\partial z} \right )$

$\omega _y=0$

$\omega _x=0$

$\omega =\omega_xi+\omega_yj+\omega_zk$

ω = 0

So the angular velocity of fluid is zero.

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Explanation:

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$P(X = 3) = \frac{e^{-0.8}*(0.8)^{3}}{(3)!} = 0.0383$

$P(X = 4) = \frac{e^{-0.8}*(0.8)^{4}}{(4)!} = 0.0077$

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using namespace std;

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double getTotal(double [], int);

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double getTotal(int rainFall,double NUM_MONTHS[])

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{getTotal(rainFall,NUM_MONTH)

average= total/NUM_MONTHS;

return average;

}

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{

double largest;

largest = NUM_MONTHS[0];

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double smallest;

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{

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cout << (month + 1) << ": ";

cin >> rainFall[month];

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cout << fixed << showpoint << setprecision(2) << endl;

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cout << getAverage(rainFall, NUM_MONTHS)

<< " inches." << endl;

int subScript;

cout << "The largest amount of rainfall was ";

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<< " inches in month ";

cout << (subScript + 1) << "." << endl;

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<< " inches in month ";

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