Answer:
The force induced on the aircraft is 2.60 N
Solution:
As per the question:
Power transmitted,
Now, the force, F is given by:
(1)
where
v = velocity
Now,
For a geo-stationary satellite, the centripetal force, is provided by the gravitational force,
:
Thus from the above, velocity comes out to be:
where
R =
R =
where
G = Gravitational constant
T = Time period of rotation of Earth
R is calculated as 42166 km
Now, from eqn (1):
F = 2.60 N
is the volume of the sample when the water content is 10%.
<u>Explanation:</u>
Given Data:
First has a natural water content of 25% = = 0.25
Shrinkage limit,
We need to determine the volume of the sample when the water content is 10% (0.10). As we know,
------> eq 1
The above equation is at ,
Applying the given values, we get
Shrinkage limit is lowest water content
Applying the given values, we get
Applying the found values in eq 1, we get
Answer:
The radius of a wind turbine is 691.1 ft
The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m
Explanation:
Given;
power generation potential (PGP) = 1000 kW
Wind speed = 5 mph = 2.2352 m/s
Density of air = 0.0796 lbm/ft³ = 1.275 kg/m³
Radius of the wind turbine r = ?
Wind energy per unit mass of air, e = E/m = 0.5 v² = (0.5)(2.2352)²
Wind energy per unit mass of air = 2.517 J/kg
PGP = mass flow rate * energy per unit mass
PGP = ρ*A*V*e
r = 210.64 m = 691.1 ft
Thus, the radius of a wind turbine is 691.1 ft
PGP = CVᵃ
For best design of wind turbine Betz limit (c) is taken between (0.35 - 0.45)
Let C = 0.4
PGP = Cvᵃ
take log of both sides
ln(PGP) = a*ln(CV)
a = ln(PGP)/ln(CV)
a = ln(1000)/ln(0.4 *2.2352) = 7.73
The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m