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vodomira [7]
1 year ago
5

technician a says that dirt bypassing the filter on many common rail injectors can cause an injector to stick open and continuou

sly fuel a cylinder. technician b says that any dirt particles may potentially damage the injector, but would not allow an injector to full fuel or the engine to run away. who is correct?
Engineering
1 answer:
NNADVOKAT [17]1 year ago
3 0

Technician a is correct because he says that Many common rail injectors filters can be bypassed by dirt, which can lead to an injector sticking open and continuously fueling a cylinder.

Coalescence is used to separate the water and fuel. To the fuel injector cleaning kit, fasten your air compressor. Diesel engines run at compression ratios that are greater than those of gasoline engines. greater ratio compared to gasoline engines. increased thermal expansion as a result. more fuel energy that is transformed into usable power. The great benefit of using a dry cylinder sleeve is that by quickly installing new sleeves, the cylinder block can be quickly restored to its original specifications. Vacuum drying can be used to get rid of small amounts of water. A nozzle is used to spray the fuel into the vacuum chamber of engines. Air and unsolved free water are taken out of the oil. The fuel is evenly dispersed, which facilitates efficient drying.

Learn more about injectors here:

brainly.com/question/27969202

#SPJ4

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23 PM Sat Apr 10
worty [1.4K]
Uhm I’m not understanding the question
4 0
3 years ago
which acpi power state allows a system to start where it left off, but all other components are turned off? sleeping mechanical
Katena32 [7]

Answer:I don’t know.

Explanation:I work for carrier and we haven’t really gotten into that yet.

3 0
3 years ago
Consider a cubic block whose sides are 6 cm long and a cylindrical block whose height and diameter are also 6 cm. both blocks ar
bija089 [108]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

5 0
3 years ago
After having done the hand calculation and pseudocode for a program that models inflating a spherical balloon, now implement the
vampirchik [111]

Answer:

Explanation:

CODE :

import java.util.Scanner; // required imports for the class

class Balloon { // class to run the code

public static void main(String[] args) { // driver method

Scanner in = new Scanner(System.in); // scanner class to get the data

System.out.print("Diameter: "); // message

double diameter = in.nextDouble(); // prompt

double growth = 1; // local variables

int c = 0;

while (c < 10) { // iterate over the loop

double radius = diameter / 2; // calculate the radius

double vol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the initial volume

diameter = growth + diameter; // update the diamter

System.out.printf("\nIncrease in the Diameter is : %.0f", growth); // message

System.out.println("\nNew Diameter is : " + diameter); // print the diameter

radius = diameter / 2; // calculate the new diameter

double growthvol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the new volume

System.out.printf("Increase in the Volume is : %.0f", growthvol - vol); // message

System.out.println("\nNew Volume is : " + growthvol); // message

c++; // increment the count

}

}

}

OUTPUT :

run 1 :

Diameter: 10

Increase in the Diameter is : 1

New Diameter is : 11.0

Increase in the Volume is : 173

New Volume is : 696.5566666666667

Increase in the Diameter is : 1

New Diameter is : 12.0

Increase in the Volume is : 208

New Volume is : 904.3199999999998

Increase in the Diameter is : 1

New Diameter is : 13.0

Increase in the Volume is : 245

New Volume is : 1149.7633333333333

Increase in the Diameter is : 1

New Diameter is : 14.0

Increase in the Volume is : 286

New Volume is : 1436.0266666666666

Increase in the Diameter is : 1

New Diameter is : 15.0

Increase in the Volume is : 330

New Volume is : 1766.25

Increase in the Diameter is : 1

New Diameter is : 16.0

Increase in the Volume is : 377

New Volume is : 2143.5733333333333

Increase in the Diameter is : 1

New Diameter is : 17.0

Increase in the Volume is : 428

New Volume is : 2571.1366666666668

Increase in the Diameter is : 1

New Diameter is : 18.0

Increase in the Volume is : 481

New Volume is : 3052.08

Increase in the Diameter is : 1

New Diameter is : 19.0

Increase in the Volume is : 537

New Volume is : 3589.5433333333335

Increase in the Diameter is : 1

New Diameter is : 20.0

Increase in the Volume is : 597

New Volume is : 4186.666666666667

run 2 :

Diameter: 7.5

Increase in the Diameter is : 1

New Diameter is : 8.5

Increase in the Volume is : 101

New Volume is : 321.39208333333335

Increase in the Diameter is : 1

New Diameter is : 9.5

Increase in the Volume is : 127

New Volume is : 448.6929166666667

Increase in the Diameter is : 1

New Diameter is : 10.5

Increase in the Volume is : 157

New Volume is : 605.82375

Increase in the Diameter is : 1

New Diameter is : 11.5

Increase in the Volume is : 190

New Volume is : 795.9245833333334

Increase in the Diameter is : 1

New Diameter is : 12.5

Increase in the Volume is : 226

New Volume is : 1022.1354166666666

Increase in the Diameter is : 1

New Diameter is : 13.5

Increase in the Volume is : 265

New Volume is : 1287.59625

Increase in the Diameter is : 1

New Diameter is : 14.5

Increase in the Volume is : 308

New Volume is : 1595.4470833333332

Increase in the Diameter is : 1

New Diameter is : 15.5

Increase in the Volume is : 353

New Volume is : 1948.8279166666664

Increase in the Diameter is : 1

New Diameter is : 16.5

Increase in the Volume is : 402

New Volume is : 2350.87875

Increase in the Diameter is : 1

New Diameter is : 17.5

Increase in the Volume is : 454

New Volume is : 2804.7395833333335

Description :

During the casting or the calculation of the volume and the radius the RHS needs to be casted for the numerator with the double datatype so as to clearly get the result. And that the formula is also been updated.

Hope this is helpful.

7 0
3 years ago
Which term describes erosion?
Vera_Pavlovna [14]

Answer:

transports solid materials

7 0
3 years ago
Read 2 more answers
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