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3 years ago

If you had 2.50 moles of anything, how many of those things would you have?

Chemistry

1 answer:

Wittaler [7]3 years ago

7 0

Answer:

1.51 x 10²⁴ things

Explanation:

According to Avogadro's Constant.

1 mole of any substance, constains 6.02×10²³ particles of that subtance.

From the question,

If we have 2.50 moles of anything,

1 mole of anything ⇒ 6.02×10²³ things

2.50 moles of anything ⇒ y things

solving for y

y = (2.50× 6.02×10²³)/1

y = 15.05×10²³

y = 1.505×10²⁴

y ≈ 1.51×10²⁴

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Calculate the volume, in milliliters, for the following:

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Answer: The volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

The volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

Explanation:

Molarity is the number of moles of solute present in a liter of solution.

As given moles of $NaNO_{3}$ are 0.850 mol and molarity of $NaNO_{3}$ solution is 0.5 M. Hence, its volume is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\0.5 M = \frac{0.850 mol}{Volume}\\Volume = 1.7 L (1 L = 1000 mL)\\= 1700 mL$

Therefore, the volume for 0.850 mol of $NaNO_{3}$ from a $NaNO_{3}$ solution is 1700 mL.

As given mass of LiOH are 30.0 g from a 2.70 M LiOH (molar mass = 23.95 g/mol) solution. Hence, its number of moles are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{30.0 g}{23.95 g/mol}\\= 1.25 mol$

So, volume for LiOH solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\2.70 M = \frac{1.25}{Volume}\\Volume = 0.464 L (1 L = 1000 mL)\\= 464 mL$

Therefore, volume of 30.0 g of LiOH from a 2.70 M LiOH solution is 464 mL.

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