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2 years ago

I need help on this 1+s=3

Mathematics

1 answer:

11111nata11111 [884]2 years ago

7 0

Answer:

s = 2

Step-by-step explanation:

3 - 1 = 2

1 + 2 = 3

Hopefully this helps :3 Sorry if wrong :( Plz mark brainiest if correct :D Your bootiful/handsome! Have a great day luv <3

-Bee~

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2 years ago

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Let f(x)=x^2+6x−16.<br> Enter the x-intercepts of the quadratic function in the boxes.

Sauron [17]

$\underline{\underline{\large\bf{Given:-}}}$

$\red{\leadsto}\:$ $\textsf{}$ $\sf f(x)= x^2+6x−16$

$\underline{\underline{\large\bf{To Find:-}}}$

$\orange{\leadsto}\:$ $\textsf{ x-intercepts of the quadratic function }$ $\sf$

$\\$

$\underline{\underline{\large\bf{Solution:-}}}\\$

$\longrightarrow$ x- intercept is the point where graph of given function touches the x-axis,f(x) becomes 0 at the point where graph of given function touches the x-axis. Therefore, we would to solve x^2+6x−16=0 and find its root.

$\begin{gathered}\\\implies\quad \sf x^2+6x−16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x^2+8x-2x −16=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x(x+8)-2(x+8)=0 \\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf (x-2)(x+8)=0\\\end{gathered}$

$\begin{gathered}\\\implies\quad \sf x=2\quad or \quad x=-8 \\\end{gathered}$

$\leadsto$ x-intercepts of the given quadratic function are 2 and -8 .

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2 years ago

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tatyana61 [14]

Answer:

The mean.

Step-by-step explanation:

The mean is not robust.

The presence of an outlier greatly affects the value of a mean.

An example will illustrate this.

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34 is an outlier. The mean = (2+3+5+6+34) / 5 = 10.

Now if we replace the outlier with a number closer to the others:

Say we have 2 3 5 6 8 :

The mean = (2+3+5+6+8) / 5 = 4.8 which is a much truer measure of centrality than 10.

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The correct answer is B.

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Thus, our equation is 36x-64

Hope this helps!

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