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harkovskaia [24]
3 years ago
10

please help with this. I got the first choice when I picked wrong so i would like help on a second attempt. thanks ​

Mathematics
1 answer:
SpyIntel [72]3 years ago
3 0

Answer:

4

Step-by-step explanation:

im pretty sure that's the right answer!! let me know if I'm right

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Which two shapes make up the first split of quadrilaterals on the quadrilateral hierarchy?
s2008m [1.1K]

Trapezoid and kite make up the first split of quadrilaterals on the quadrilateral hierarchy

<h3>What is a quadrilateral?</h3>

A quadrilateral is a polygon that has four sides and four angles. Types of quadrilateral are<em> square, kite, trapezoid, rectangle, rhombus </em>and so on.

A quadrilateral hierarchy is a graphical way of representing the different types of quadrilaterals.

Trapezoid and kite make up the first split of quadrilaterals on the quadrilateral hierarchy

Find out more on quadrilateral at: brainly.com/question/23935806

#SPJ1

7 0
2 years ago
Triangles ABC and DEF are similar.
vivado [14]
All I can really remember is find the scale factor and divide it by the segment
3 0
3 years ago
Joey built a model sailboat that is similar to his real sailboat. The triangular sail on
lord [1]

Answer:

31.25

Step-by-step explanation:

25/12=2.083333

15 x 2.0833333=31.24999999995

round up to get 31.25

3 0
3 years ago
Let θ be an angle in quadrant IV such that sinθ = -2/5 .<br> Find the exact values of secθ and tanθ.
Gnesinka [82]

If <em>θ</em> lies in the fourth quadrant, then sin(<em>θ</em>) < 0 and cos(<em>θ</em>) > 0. So we have from the Pythagorean identity,

sin²(<em>θ</em>) + cos²(<em>θ</em>) = 1   ==>   cos(<em>θ</em>) = +√(1 - sin²(<em>θ</em>)) = √21/5

Then

sec(<em>θ</em>) = 1/cos(<em>θ</em>) = 5/√21

and

tan(<em>θ</em>) = sin(<em>θ</em>)/cos(<em>θ</em>) = (-2/5)/(√21/5) = -2/√21

8 0
3 years ago
What is the approximate length?
Usimov [2.4K]

9514 1404 393

Answer:

  (a)  75.5

Step-by-step explanation:

There are two ways you can work this.

<u>Pythagorean theorem</u>

Triangle CMP is a right triangle. CM = AC = 55. CP = CB -PB = 55 -15 = 40. Then length PM can be found from ...

  PM² +CP² = CM²

  PM = √(CM² -CP²) = √(55² -40²) = √1425 ≈ 37.749

The length MN is twice the length of PM, so is ...

  MN = 2×PM = 2×37.349 = 75.498

The length of MN is about 75.5.

__

<u>Using chord relationships</u>

The products of the different lengths for the same chord are the same for the crossed chords.

  AP×PB = MP×PN

We know MP = PN, so ...

  MP = √(AP×PB) = √((55+40)(15)) = √1425

As before, MN = 2×MP = 2√1425

  MN ≈ 75.5

4 0
3 years ago
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