Answer: It should be used 2 for type-A and 3 for type-B to minimize the cost.
Step-by-step explanation: As it is stipulated, <u>x</u> relates to type-A and y to type-B.
Type-A has 60 deluxe cabins and B has 80. It is needed a minimum of 360 deluxe cabins, so:
60x + 80y ≤ 360
For the standard cabin, there are in A 160 and in B 120. The need is for 680, so:
160x + 120y ≤ 680
To calculate how many of each type you need:
60x + 80y ≤ 360
160x + 120y ≤ 680
Isolating x from the first equation:
x = 
Substituing x into the second equation:
160() + 120y = 680
-3200y+1800y = 10200 - 14400
1400y = 4200
y = 3
With y, find x:
x =
x = 
x = 2
To determine the cost:
cost = 42,000x + 51,000y
cost = 42000.2 + 51000.3
cost = 161400
To keep it in a minimun cost, it is needed 2 vessels of Type-A and 3 vessels of Type-B, to a cost of $161400
Answer:
this might be it : 12xy+228y
Step-by-step explanation:
you multiply 2 by 3 and get 6 and then multiply by 2 again and add they y
and then multiply 52 by 2 and gte 104 and them multiply by 2 and get 228 and add they y
Answer:
y = 6x + 0
Step-by-step explanation:
Equation of a line
y = mx + c
Given
( 0 , 0) ( -1/2 , -3)
find the slope m
m = y2 - y1 / x2 - x1
x1 = 0
y1 = 0
x2 = -1/2
y2 = -3
Insert the values
m = y2 - y1 / x2 - x1
m = -3 - 0 / -1/2 - 0
= -3/-1/2
Minus cancels minus
= 3/1/2
= 3/1 ÷ 1/2
= 3/1 × 2/1
= 6/1
= 6
m = 6
Substitute any of the two points given into the equation of a line
y = mx + c
Where
y - intercept point y
x - intercept point x
m - slope of the line
c - intercept
(-1/2 , -3)
x = -1/2
y = -3
-3 = 6(-1/2) + c
-3 = -6/2 + c
-3 = -3 + c
-3 + 3 = c
c = 0
y = 6x + 0
The equation of the line is
y = 6x + 0
20% decrease should be the answer
