This graph shows a proportional relationship. What is the constant of proportionality? Enter your answer as a ratio in simplified form in the box.
The anser is 6/8 that what i think
Answer:
5.
Step-by-step explanation:
The size of the population increases when the growth rate is positive and
decreases for a negative growth rate.
The completed table is presented as follows;
![\begin{array}{|c|c|c|}2003 \ Population (millions)&Projected \ 2029 \ Population \ (millions)&Growth \ rate \ K \\40.5&20.9&-2.255\%\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cc%7C%7D2003%20%5C%20Population%20%28millions%29%26Projected%20%5C%202029%20%5C%20Population%20%5C%20%28millions%29%26Growth%20%5C%20rate%20%5C%20%20K%20%5C%5C40.5%2620.9%26-2.255%5C%25%5Cend%7Barray%7D%5Cright%5D)
Reasons:
The table is presented as follows;
![\begin{array}{|c|c|c|}2003 \ Population (millions)&Projected \ 2029 \ Population \ (millions)&Growth \ rate \ K \\40.5&20.9&\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cc%7C%7D2003%20%5C%20Population%20%28millions%29%26Projected%20%5C%202029%20%5C%20Population%20%5C%20%28millions%29%26Growth%20%5C%20rate%20%5C%20%20K%20%5C%5C40.5%2620.9%26%5Cend%7Barray%7D%5Cright%5D)
The population in growth rate is given by the following formula;
P = a·(1 + r)ˣ
Where;
a = The initial population in 2003 = 40.5 million
P = The population in 2029 = 20.9 million
x = The number of years = 2029 - 2003 = 26
Therefore;
20.9 = 40.5 × (1 + r)²⁹


The population growth rate is r ≈ -0.02255 = -2.255 %
The completed table is therefore;
![\begin{array}{|c|c|c|}2003 \ Population (millions)&Projected \ 2029 \ Population \ (millions)&Growth \ rate \ K \\40.5&20.9&-2.255\%\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cc%7Cc%7Cc%7C%7D2003%20%5C%20Population%20%28millions%29%26Projected%20%5C%202029%20%5C%20Population%20%5C%20%28millions%29%26Growth%20%5C%20rate%20%5C%20%20K%20%5C%5C40.5%2620.9%26-2.255%5C%25%5Cend%7Barray%7D%5Cright%5D)
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brainly.com/question/25354980
5y - 2x + 1 = 0.
5y = 2x-1.
y = 2/5 x - 2/5
this tells us that tan(theta) = 2/5
sin(theta)/sqrt(1-sin^2(theta)) = 2/5
x/sqrt(1-x^2)=2/5
x^2/(1-x^2)=4/25
25x^2=4-4x^2
29x^2=4
x^2=4/29
x = -2/sqrt(29) because quadrant III
cos(x) = sqrt(1-4/29) = -5/sqrt(29)
tan(theta)=2/5
cos(theta)=-5/sqrt(29)
sin(theta)=-2/sqrt(29)
cot(theta)=5/2
sec(theta)=-sqrt(29)/5
csc(theta)=-sqrt(29)/2