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3 years ago

What's a verbal expression for 5m^2+2

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

This can be expressed as five m squared plus two.

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Which are equivalent to −6(b+2)+8 chose all that apply −6b+2+8 −6b−4 None of the above

xeze [42]

None of the above are equivalent to -6(b+2)+8

4 0

2 years ago

What can be concluded if angle 1 =angle7

Maksim231197 [3]

From the information given in the question,
the only possible conclusion is:

If angle 1 is measured and angle 7 is measured,
the two measurements will be identical.

If angle 1 and angle 7 are related to a particular shape or drawing,
then additional conclusions may be possible, but we'd need to see
the shape or drawing.

8 0

3 years ago

Which of the following is a quadratic function?

Fudgin [204]

Answer:A is a quadratic function

Step-by-step explanation:

A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero. If you solve the function, y= 2x^2+x-6.

6 0

3 years ago

By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00pm positive or negative?

Ad libitum [116K]

Answer:

Part a) The temperature at noon was -3°F

Part b) The temperature at 3:00 pm was +2°F

Part c) The temperature at 11:00 pm was -6°F

Step-by-step explanation:

The complete question is

When Leo woke up he saw that the temperature was -8°F. By noon the temperature has increased 5°F. Part a) What was the temperature at noon?

Part b) By 3:00 pm, the temperature increased by another 5 degrees Fahrenheit was the temperature at 3:00 pm positive or negative?

Part c) By 11:00 pm, the temperature had dropped 8°F. Was the

temperature at 11:00 PM positive or negative? Explain.

Part a) we know that

You can use a number line to adds the numbers

-8+5=-3°F

therefore

The temperature at noon was -3°F

Part b) we know that

the temperature increased by another 5 degrees

You can use a number line to adds the numbers

-3+5=+2°F

therefore

The temperature at 3:00 pm was +2°F

Part c) we know that

the temperature had dropped 8°F

You can use a number line to adds the numbers

2-8=-6°F

therefore

The temperature at 11:00 pm was -6°F

6 0

3 years ago

It's from the chapter : "exponents and powers" i need the workings too please help

labwork [276]

Answer:

505/19

Step-by-step explanation:

Easy

so [3^3-(1/2)^(-3)*(1/19)]

simplify

3^3-8/19

3^3=27

27-8/19

convert element to fraction

(27*19)/19-8/19

combine

(27*19-8)/19

505/19

Have a wonderful day ask me if you have more questions about MATH that goes for anyone who needs math help

5 0

3 years ago