Which of these are the prime number: 1,2,3,4,5,6,7,8

Help me guys l don't know this ??????

Over [174]

Answer:

first blank is 7

next blank is 20

Step-by-step explanation:

because 14 divided by 2 is 7

-4×5=20

8 0

3 years ago

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What is the period of the function?

blsea [12.9K]

Answer:

2pi

Step-by-step explanation:

4 0

3 years ago

Christine Wong has asked Dave and Mike to help her move into a new apartment on Sunday morning. She has asked them both in case

olga nikolaevna [1]

Answer:

(a) The probability that both Dave and Mike will show up is 0.25.

(b) The probability that at least one of them will show up is 0.75.

(c) The probability that neither Dave nor Mike will show up is 0.25.

Step-by-step explanation:

Denote the events as follows:

<em>D</em> = Dave will show up.

<em>M</em> = Mike will show up.

Given:

$P(D^{c})=0.55\\P(M^{c})=0.45$

It is provided that the events of Dave of Mike showing up are independent of each other.

(a)

Compute the probability that both Dave and Mike will show up as follows:

$P(D\cap M)=P(D)\times P (M)\\=[1-P(D^{c})]\times [1-P(M^{c})]\\=[1-0.55]\times[1-0.45]\\=0.2475\\\approx0.25$

Thus, the probability that both Dave and Mike will show up is 0.25.

(b)

Compute the probability that at least one of them will show up as follows:

P (At least one of them will show up) = 1 - P (Neither will show up)

$=1-P(D^{c}\cup M^{c})\\=P(D\cup M)\\=P(D)+P(M)-P(D\cap M)\\=[1-P(D^{c})]+[1-P(M^{c})]-P(D\cap M)\\=[1-0.55]+[1-0.45]-0.25\\=0.75$

Thus, the probability that at least one of them will show up is 0.75.

(c)

Compute the probability that neither Dave nor Mike will show up as follows:

$P(D^{c}\cup M^{c})=1-P(D\cup M)\\=1-P(D)-P(M)+P(D\cap M)\\=1-[1-P(D^{c})]-[1-P(M^{c})]+P(D\cap M)\\=1-[1-0.55]-[1-0.45]+0.25\\=0.25$

Thus, the probability that neither Dave nor Mike will show up is 0.25.

6 0

4 years ago

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Y=y = 2x -4 when x= 2

Dominik [7]

Y would equal 0. 2x2=4 and 4-4=0.

7 0

3 years ago

I need help with #65 to #70 ASAP please and thank you …. Could someone please help me with it… I need to get it done ASAP… it is

never [62]

All of the given questions(#65 to #70) are AP(s).

Formula to be used: a(n) = a(1) + (n - 1)d

Pronounced as:

nth term = 1st term + (n - 1)d, where d is the common difference.

*d = difference of any two consecutive terms.

65):

1st term = 2, d = 6 - 2 = 4

Therefore,

11th term = 2 + (11 - 1)4 = 42

66):

1st term = 5, d = 15 - 5 = 10

Therefore,

16th term = 5 + (16 - 1)10 = 155

67):

1st term = 19, d = 39 - 19 = 20

Therefore,

21st term = 19 + (21 - 1)20 = 419

68):

1st term = 8, d = 38 - 8 = 30

Therefore,

36th term = 8 + (36 - 1)30 = 1058

69):

1st term = 1/2, d = 1 - 1/2 = 1/2

Therefore,

101st term = 1/2 + (101 - 1)1/2 = 101/2

70):

1st term = 0.75, d = 1.50 - 0.75 = 0.75

Therefore,

151st term = 0.75 + (151 - 1)(0.75) = 113.25

8 0

3 years ago