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alina1380 [7]
3 years ago
13

Yes or no and explain?

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

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Farmer Ben has only ducks and cows. He can’t remember how many of each he has, but he doesn’t need to remember because he knows
Maru [420]

Answer:

12 cows - 48 legs

4 ducks- 8 legs

- there are many different numbers you can do but if you want to change the numbers and have more ducks then: for every one cow you take away two more ducks.

Step-by-step explanation:

22 total animals

56 total legs

ducks have 2 legs

cows have 4 legs

12 times 4 = 48 ( 12 cows with 4 legs each cow =  48 legs)

4 times 2 = 8 ( 4 ducks with 2 legs each duck = 8 legs)

6 0
2 years ago
The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

4 0
3 years ago
The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either
kompoz [17]

The Rome data center is best described by the mean. The New York data center is best described by the median. The third option C is correct.

<h3>The Mean and Median:</h3>

The mean of a data set is the average of all the terms in the data set. The median of a data set is the value of the midpoint term in the frequency distribution.

From the given information, the table can be better expressed as:

           High   Low   Q1     Q3    IQR   Median    Mean         σ

Rome   18         1        3       7        4         6.5        6.4           4.3

NY        14         1       4.5    8.5      4        5.5        6.1            3.2

  • From the data sets in the table, the distribution for Rome is not largely diverse, and there isn't much departure from the mean value. It indicates that in the data set of Rome families, no outliers have occurred.

  • In New York, the data indicate a distinct outlier for New York families in Q3. This is due to the fact that the gap is so large, the mean may not be a good choice for determining the measure of the central tendency.

Therefore, we can conclude that, the Rome data center is best described by the mean and the median will be utilized to determine the central tendency in New York.

Learn more about mean and median here:

brainly.com/question/14532771

4 0
2 years ago
Solve the inequality graph the solution 2|x+1/3|&lt;9
shtirl [24]
-29/6<x<25/6
I'm sorry I can't graph because Brainly won't take my Img. 
But I will tell you that it is a closed circle. 
3 0
3 years ago
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