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3 years ago

The volume of a cylinder with a height of 2 and radius of 3

Mathematics

1 answer:

prisoha [69]3 years ago

6 0

Answer:

v = 18π

Step-by-step explanation:

v = πr²h

plug in the givens

v = π(3²)2

v = 18π exact answer

V = 18 * 3.14 = 56.52 decimal approximation

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Write the decimals in order from least to greatest. 0.403, 0.034, 0.340

nata0808 [166]

Answer:

0.034, 0.340, 0.403

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2 years ago

Read 2 more answers

It is given that AB is parallel to CD and points E, G, H, and F are collinear. The measure of ZEGF is 180°, by the definition of

alex41 [277]

The completed statement filled in with the correct option is presented as follows;

It is given that AB is parallel to CD and points, E, G, H, and F are collinear. The measure of ‹EGF is 180° by the definition of a straight angle. ‹AGE and ‹AGF are adjacent, so the measure of ‹AGE plus the measure of ‹AGF equals the measure of angle ‹EGF. It can be said that the measure of ‹AGE plus the measure of ‹AGF equals 180°. ‹CHE and ‹AGF are same side interior angles, so the measure of angle ‹CHE plus the measure of angle ‹AGF equals 180°.

Substituting once again means that the measure of ‹AGE plus the measure of angle ‹AGF equals the measure of angle ‹CHE plus the measure of ‹AGF. The measure of angle ‹AGE is equal to the measure of ‹CHE using the Subtraction Property of Equality. Finally, by the definition of congruency, ‹AGE is congruent to ‹CHE

The correct option is therefore;

‹CHE and ‹AGE are same side interior angles; using the Subtraction Property of Equality

<h3>What relationships between angles formed by parallel lines can be used to complete the paragraph?</h3>

Angles, ‹CHE and ‹AGF are angles formed on the same side of the common transversal, EF, and are formed on the interior part of AB and CD.

Given that ‹CHE and ‹AGF are both on the line FGHE, and together with ‹CHF and ‹AGE form two linear pair angles, ‹CHE and ‹AGF are supplementary angles and add up to 180°.

According to the substitution property of equality, both sides of an equation remain equal following the subtraction of the same quantity from both sides.

Given that we have:

‹AGE + ‹AGF = ‹CHE + ‹AGF

Subtracting ‹AGF from both sides gives;

‹AGE = ‹CHE (subtraction property of equality)

Learn more about the angles formed by parallel lines here:

brainly.com/question/17430387

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1 year ago

Describe the transformation of the graph y = -(x-4)^3 +5

eduard

Reflected across the x-axis
shift right 4 units
shift up 5 units

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3 years ago

Can some one friend me plz

Alona [7]

Answer: I didn't understand

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3 years ago

There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one

diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

$P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02$

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01$

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05$

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C$

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

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4 years ago