(67 + 68 + 78 + x) / 4 = 70
(213 + x) / 4 = 70
213 + x = 70 * 4
213 + x = 280
x = 280 - 213
x = 67
(213 + x) / 4 = 79
213 + x = 79 * 4
213 + x = 316
x = 316 - 213
x = 103
lowest u can make is 67, highest u can make is 100
A. First move all to the left side of the equation(Normal form)
x^3 - 49x= 0
B. Factor out an x, which is the GCF (Factored form)
x(x^2 - 49) = 0
C. Find solutions by making each x piece equal to 0. The first part is just x=0 and the second part is just factoring the difference of squares and then solving.
x=0, x^2 - 49 =0
x=0, x + 7 = 0, x - 7 = 0
Therefore, the answers for Part C are:
x = 0, x = -7, x = 7
Sorry i don’t understand the question can you reply to this and comment
Answer:
2 roots in every case, not all are real.
Step-by-step explanation:
All of these equations are quadratic equations (degree 2). Every quadratic has two roots. They may be identical (looks like 1 root), and they may be complex (zero real roots), but there are always 2 of them.
a) the y-value of the vertex is negative and the parabola opens downward (leading coefficient -5), so there are no real zeros and both roots are complex.
b) each binomial factor contributes a root. Both roots are real.
c) the discriminant is positive, (3²-4·2·1=1), so both roots are real.
Answer: the equation would be 5n=1,500
Step-by-step explanation:
5 dollars per N (student) they need to make 1,500 so you need to find n
( to find N do 1,500 divided by 5 = 300
