Where’s the answer choices ??
Answer:
the answer is actually 0 ≤ x ≤ 5
Step-by-step explanation:
i got it right
Answer: The required equation for points P is 
Step-by-step explanation: We are give two points A(0, 1, 2) and B(6, 4, 2).
To find the equation for points P such that the distance of P from both A and B are equal.
We know that the distance between two points R(a, b, c) and S(d, e, f) is given by

Let the point P be represented by (x, y, z).
According to the given information, we have
![PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.](https://tex.z-dn.net/?f=PA%3DPB%5C%5C%5C%5C%5CRightarrow%20%5Csqrt%7B%28x-0%29%5E2%2B%28y-1%29%5E2%2B%28z-2%29%5E2%7D%3D%5Csqrt%7B%28x-6%29%5E2%2B%28y-4%29%5E2%2B%28z-2%29%5E2%7D%5C%5C%5C%5C%5CRightarrow%20x%5E2%2By%5E2-2y%2B1%2Bz%5E2-4z%2B4%3Dx%5E2-12x%2B36%2By%5E2-8y%2B16%2Bz%5E2-4z%2B4~~~~~~~%5B%5Ctextup%7BSquaring%20both%20sides%7D%5D%5C%5C%5C%5C%5CRightarrow%20-2y%2B1%3D-12x-8y%2B52%5C%5C%5C%5C%5CRightarrow%2012x%2B6y%3D51%5C%5C%5C%5C%5CRightarrow%204x%2B2y%3D17.)
Thus, the required equation for points P is 
I believe the answer to this30+5+.2+.04+.005
Answer:
(x, y) = (40, 30)
Step-by-step explanation:
A graphing calculator can show you the solution to this system of equations is (x, y) = (40, 30). That is the point of intersection where the two lines cross.
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An algebraic solution can be found by using the substitution method. An expression for y can be found using the second equation:
y = 110 -2x . . . . . . subtract 2x from both sides
Using this in the first equation gives ...
3x -4(110 -2x) = 0 . . . . substitute for y
11x = 440 . . . . . . . . . simplify, add 440
x = 40 . . . . . . . . . . divide by 11
y = 110 -2(40) = 30
The solution is (x, y) = (40, 30).