Answer:
-2z+8
Step-by-step explanation:
3z+2+(-5z)+6
3z+2-5z+6
-2z+2+6
-2z+8
I presume this is meant to be exponential.
When f(x) = a(b)^x, a represents the starting value, b represents change, and x represents time.
The population began in 2000 (x = 0). This makes the equation equal to 78,500, which is your starting value and population in 2000.
1.02 means that the initial value is multiplied by 1.02 or 102% each year. Therefore, there is a 2% increase.
Answer:
the question is incomplete, so I looked for a similar one:
<em>After the release of radioactive material into the atmosphere from a nuclear power plant, the hay was contaminated by iodine 131 ( half-life, 8 days). If it is all right to feed the hay to cows when 10% of the iodine 131 remains, how long did the farmers need to wait to use this hay? </em>
iodine's half life (we are given x, we need to find b):
0.5A₀ = A₀eᵇˣ
x = 8 days
we eliminate A₀ from both sides
0.5 = eᵇ⁸
ln 0.5 = ln eᵇ⁸
-0.69315 = b8
b = -0.69315 / 8 = -0.08664
since the farmers need to wait until only 10% of the iodine remains (we already calculated b, now we need to find x):
0.1A₀ = A₀eᵇˣ
0.1 = eᵇˣ
ln 0.1 = bx
where b = -0.08664
x = ln 0.1 / -0.08664 = -2.302585 / -0.08664 = 26.58 days
Answer:
Step-by-step explanation:
Answer:
c ∛ (16)
Step-by-step explanation:
2 ^ (4/3)
We can separate this into 2 pieces using the power of power rule in reverse
x^a ^b = x^ (ab)
(2^4 ) ^ 1/3
2 to the 4th power is
16 ^ (1/3)
We now have the cubed root of 16
∛ (16)