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Vadim26 [7]
2 years ago
5

Consider the sequence 100, 50, 25,12.5 ... Can it arithmetic? Can it be geometric? why?

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
3 0

Answer:

(a) Arithmetic? No. Geometric? YES!

(b) The terms will never become zero or negative.

Step-by-step explanation:

<h2>Explaining part (a)</h2>

An aritmetic sequence has the same difference between each term, positive or negative.

Example:  1, 4, 7, 10, 13, ...  the difference between consecutive terms is always 3

Example:  0, -2, -4, -6, -8, ... the difference between consecutive terms is always -2

A geometric sequence has the same ratio (or multiplier) between consective terms, positive or negative, causing an increase or a decrease.

Example: 1, 2, 4, 8, 16, ...  each term is 2x the term before it

Example: 64, 32, 16, 8, 4, 2, 1, (1/2), (1/4), (1/8), ...each term is half the term before

Example: +91, -27, +9, -3, +1, -1/3, +1/9. -1/27, ... each term is -1/3 of term before

In the given sequence, we can see that the difference between terms is not always the same number. 100 - 50 = 50, but 50 - 25 = 25, not 50.

However, we do see that each term is half the term before it. That is definitely geometric.

<h2>Explaining part (b)</h2>

For 100, 50, 25, 12.5, ... we get each term by multiplying the previous term by (1/2), which is a positive number. No matter how many times you multiply by a positive, you'll never get a negative or get a zero.

Multiply by 1/2 enough times, and you get as small a positive number as you like, but it will always be positive, even if you get down to billionths or trillionths.

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Correct option C) 0.98%

<u>Step-by-step explanation:</u>

We know that  , there are 2 black ace cards out of 52 cards in a deck & 13 hearts out of 52 cards . Here we have to tell What is the probability of drawing a black ace followed by a heart out  of a deck when the cards aren't replaced . Let's find out:

Firstly , a black ace is drawn , so probability :

⇒ P(Black) = \frac{2}{52}

Now , A heart is drawn out of 51 cards ( as one black ace is already drawn !):

⇒ P(Heart) = \frac{13}{51}

So , Probability of occurring both events is :

⇒ P(Black)(P(Heart))

⇒ \frac{2}{52} (\frac{13}{51} )

⇒ 0.0098

Percentage = 0.0098(100) = 0.98%

Therefore , Correct option C) 0.98%

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An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
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Answer:

A) The best way to picture this problem is with a probability tree, with two steps.

The first branch, the person can choose red or blue, being 2 out of five (2/5) the chances of picking a red marble and 3 out of 5 of picking a blue one.

The probabilities of the second pick depends on the first pick, because it only can choose of what it is left in the urn.

If the first pick was red marble, the probabilities of picking a red marble are 1 out of 4 (what is left of red marble out of the total marble left int the urn) and 3 out of 4 for the blue marble.

If the first pick was the blue marble, there is 2/4 of chances of picking red and 2/4 of picking blue.

B) So a person can have a red marble and a blue marble in two ways:

1) Picking the red first and the blue last

2) Picking the blue first and the red last

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Step-by-step explanation:

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