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Xelga [282]
3 years ago
8

I really need help with this, ill give brainly.

Mathematics
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

the rate of change is-3 2

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I’m a bit stuck on the second part of what y = x, can someone help me?
marissa [1.9K]
The answer should be 3, -1
4 0
2 years ago
Question 5 of 10
Marysya12 [62]

Answer:

D

Step-by-step explanation:

7 0
3 years ago
What is the sum (Two-fifths x + StartFraction 5 over 8 EndFraction) + (one-fifth x minus one-fourth)?
liubo4ka [24]

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Step-by-step explanation:

To add or subtract 2 fractions, they must have same denominators, if they not do that

  • Find the Lowest common multiple of the two denominators (LCM)
  • Replace each denominator by it
  • Divide The LCM by each denominator and multiply the numerator of each fraction by its quotient

∵ ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} )

- Let us start with adding the like terms

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = (

∵ ( \frac{2}{5} x + \frac{1}{5} x ) have same denominators, then we can add them

∴ ( \frac{2}{5} x + \frac{1}{5} x ) = \frac{3}{5} x

∵  ( \frac{5}{8}  - \frac{1}{4} ) do not have the same denominators, then we must find

    LCM of 8 and 4

- The LCM of 8 and 4 is 8 because 8 is the first common multiple

   of 8 and 4

∵ LCM of 8 and 4 is 8

- Divide 8 by the denominator 4

∵ 8 ÷ 4 = 2

- Multiply the numerator of the fraction by 2

∴ \frac{1}{4}=\frac{2}{8}

∴  ( \frac{5}{8}  - \frac{1}{4} ) = ( \frac{5}{8} - \frac{2}{8} ) = \frac{3}{8}

∴  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) = \frac{3}{5} x +  \frac{3}{8}

The sum of  ( \frac{2}{5} x + \frac{5}{8} ) + ( \frac{1}{5} x - \frac{1}{4} ) is  \frac{3}{5} x +  \frac{3}{8}

Learn more:

You can learn more about the fractions in brainly.com/question/2456302

#LearnwithBrainly

7 0
3 years ago
Read 2 more answers
Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s
ehidna [41]
The answer is <span>104 x times the square root of 5 x 
</span>
<span>11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
</span>11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245}  *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\  \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\  \\ =11* \sqrt{5}  * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\  \\ &#10;=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\  \\ &#10;=77x* \sqrt{5*x} +27x* \sqrt{5*x}  = \\  \\ &#10;=77x \sqrt{5x} +27x \sqrt{5x} = \\  \\ &#10;=104x \sqrt{5x}
4 0
3 years ago
Read 2 more answers
There are 7052 boys and adults at carnival.
Basile [38]

Answer:

There are 6,296 children at the carnival

Step-by-step explanation:

The number of each group of people can be expressed as;

Number of boys (b)+number of adults (a)=7,052

b+a=7,052....equation 1

Number of girls (g)=Number of adults (a)-756

g=a-756....equation 2

But Number of girls (g)=number of boys (b)

Replacing the value of b in equation 1 with that of g in equation 2;

(a-756)+a=7,052

a+a=7,052+756

2 a=7,808

a=7,808/2

a=3,904

Replace the value of a in equation 2 with 3,904

g=3,904-756

g=3,148

But since g=b

g=b=3,148

b=3,148

Total number of children=Total number of boys (b)+total number of girls (g)

Total number of children=b+g

where;

b=3,148

g=3,148

replacing;

Total number of children=(3,148+3,148)=6,296

There are 6,296 children at the carnival

6 0
3 years ago
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